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Maurinko [17]
3 years ago
15

A quick USB charger claims its output current is 1.97Amp. We know that the standard USB output voltage is 5V. What is the output

power of the charger in unit of watt?
Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

Output power of the charger is 9.85 watts.

Explanation:

It is given that,

Output current of the USB charger, I = 1.97 A

The standard USB output voltage, V = 5 V

We need to find the output power of the charger. It can be determined using the following formula as :

P = V × I

P=5\ V\times 1.97\ A

P = 9.85 watts

The output power of the charger is 9.85 watts. Hence, this is the required solution.

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Steve does 80 J of work to a rope threaded through a pulley and attached to a crate of anvils. The tension of the rope is 10 N a
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The Answer is (B)

Explanation:

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The driver of a car applies the brakes for 4.0 s.As a result an average force of 7500N is exerted in the car to slow it down.Wha
Sindrei [870]

Answer:

The change in momentum of the car is  30,000 kg m/s                  

Explanation:

Given,

The force exerted on the car to slow down, F = 7500 N

The time period of force, t = 4 s

The rate of change of momentum of the object is equal to the force acting on it.

Therefore,

                                   <em> (mv - mu) / t = F</em>

Where v and u are the final and initial velocity of the car. The change in momentum of the car,

                                    mv - mu = F x t

                                                   = 7500 x 4

                                                   = 30,000 kg m/s

Hence the change in momentum of the car is  30,000 kg m/s                  

7 0
3 years ago
The energy of a wave is directly proportional to the square of the ___. D.Amplitude c. crest b. wavelength a.frequency
IRISSAK [1]

The energy of a wave is directly proportional to the square of the D.Amplitude

the energy of a wave is given as

E = (0.5) (μ v t ) w² A²

where t = time

μ = mass per unit length of the string

v = wave propagation of velocity.

w = angular frequency

A = amplitude

E = energy of wave

From the equation , we see that

the energy of wave "E" is directly proportional to A².

hence the correct choice is D. Amplitude.

4 0
3 years ago
The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points rad
Igoryamba

Answer:

Q = -52.56 nC

Explanation:

The electric field outside a spherical shell is given by

E = \frac{k*Q}{r^{2} }

where:

Q is the net  charge

r is the radius of the spherical shell and E is the electric field magnitude.

Given:

r = 0.725 m

since the field points radially toward the center of the sphere, E = -899 N/C.

k is a constant with a value = 8.99 x 109 Nm²/C².

∴-899  = \frac{8.99*10^{9} *Q}{0.725^{2}  }

Q  = \frac{-899*0.725^{2}  }{8.99*10^{9} }=-5.256*10^{-8}

Q = -52.56 nC

8 0
3 years ago
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