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3 years ago

SOMONE PLEASE HELP ASAP!!!!

Physics

1 answer:

Anna11 [10]3 years ago

7 0

Answer:

from vacuum to air

Explanation:

Refraction is a property of lightwave, in which it changes speed as it passes the boundary between two media.

When light travels from a denser medium to a less dense medium, the light wave speeds up and bends away from the normal.
Also when light travels from a less dense medium to a denser medium, the light wave slows down and bends toward the normal.

The correct option must be from a less dense medium to a denser medium.

density of glass = 2500 kg/m³

density of air = 1.275 kg/m³

density of ice = 919 kg/m³

density of water = 1000 kg/m³

density of plastic = 940 kg/m³

density of vacuum = 6.5 x 10⁻²⁷ kg/m³

The two possible options are;

from ice to water

from vacuum to air

The difference in densities of ice and water is not larger compared to vacuum and air.

If you are required to choose two options, the two options are correct

But if it is only one option, then from vacuum to air is the correct answer.

Therefore, the correct option is from vacuum to air

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Answer:

D physiological condition

Explanation:

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All neutron stars are things that produce intense gravity. All neutron stars are extremely dense objects. Therefore, all extreme

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Answer:

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Major term is given by the predicate part of the conclusion
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4 years ago

An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-

kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle $(m_1)=3\times 10^{-28} kg$

mass of heavier Particle $(m_2)=1.51\times 10^{-27} kg$

speed of lighter particle $(v_1)=0.834 c$

Let speed of heavier particle $=v_2$

and Momentum of the particle is given by

$P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}$

$P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}$

$P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}$

$P_1=8.219\times 10^{-28} kg c$

$P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

as momentum is conserved therefore $P_1=P_2$

$8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

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3 years ago

A point charge Q at the center of a sphere of radius R produces an electric flux of Î¦ coming out of the sphere. If the charge r

Dafna1 [17]

Remains the same

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3 years ago

Learning Goal: To review the concept of conservative forces and to understand that electrostatic forces are, in fact, conservati

CaHeK987 [17]

Explanation:

The electrostatic forces are conservative forces!

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$\vec E=\frac{Q}{4\pi \epsilon _0 r^2} .\^r$

and the curl expression is:

$\nabla\times \vec E=\frac{1}{r^2{\sin}\,\theta}\left|\begin{matrix}\hat{r} & r\,\hat{\theta} & r\,{\sin}\,\theta\,\hat{\varphi} \\& & \\\frac{\partial}{\partial r} & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial \varphi}\\ & & \\E_r & rE_\theta & r{\sin}\,\theta\, E_\varphi\end{matrix}\right|=(0, 0, 0)$

to find the expression for the potential function associated:

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