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3 years ago

SOMONE PLEASE HELP ASAP!!!!

Physics

1 answer:

Anna11 [10]3 years ago

7 0

Answer:

from vacuum to air

Explanation:

Refraction is a property of lightwave, in which it changes speed as it passes the boundary between two media.

When light travels from a denser medium to a less dense medium, the light wave speeds up and bends away from the normal.
Also when light travels from a less dense medium to a denser medium, the light wave slows down and bends toward the normal.

The correct option must be from a less dense medium to a denser medium.

density of glass = 2500 kg/m³

density of air = 1.275 kg/m³

density of ice = 919 kg/m³

density of water = 1000 kg/m³

density of plastic = 940 kg/m³

density of vacuum = 6.5 x 10⁻²⁷ kg/m³

The two possible options are;

from ice to water

from vacuum to air

The difference in densities of ice and water is not larger compared to vacuum and air.

If you are required to choose two options, the two options are correct

But if it is only one option, then from vacuum to air is the correct answer.

Therefore, the correct option is from vacuum to air

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A steady beam of alpha particles (q = + 2e, mass m = 6.68 × 10-27 kg) traveling with constant kinetic energy 22 MeV carries a cu

cluponka [151]

Answer:

Explanation:

q = 2e = 3.2 x 10^-19 C

mass, m = 6.68 x 10^-27 kg

Kinetic energy, K = 22 MeV

Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A

(a) time, t = 2.8 s

Let N be the alpha particles strike the surface.

N x 2e = q

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N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8

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(b) Length, L = 16 cm = 0.16 m

Let N be the alpha particles

K = 0.5 x mv²

22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²

v² = 1.054 x 10^15

v = 3.25 x 10^7 m/s

So, N x 2e = i x t

N x 2e = i x L / v

N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)

N = 4153.85

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4 years ago

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Answer:

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Grams is another unit for mass.

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3 years ago

Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?

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Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

$\frac{mv^{2}}{2} = mgh$

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Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

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Answer:

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