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mixer [17]
3 years ago
6

Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the

two cars stick together What is the total momentum of the system after the collision? O 800 kg . m/s m, = 600 kg V,= 4 m/s m = 400 kg v2 = 0 m/s 1,600 kg. m/s 0 2,400 kg • m/s 0 4,000 kg . m/s After Collision ​
Physics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

llollk

Explanation:

erma4kov [3.2K]3 years ago
7 0

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

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An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
Papessa [141]

Answer:

\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is \dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )

Now, using the pulse spread formula:

\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda

\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ )  \times (45 \ nm)

Thus, the pulse spreading as a result of  material dispersion is:\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

3 0
3 years ago
Two people are standing on a 3.12-m-long platform, one at each end. The platform floats parallel to the ground on a cushion of a
Ann [662]

Answer:

The magnitude of displacement is 0.082m

Explanation:

While the ball is in motion,we have MV + mv= 0 ...eq1

Where M = combined mass of the platform and the two people.

V = velocity of the platform

m = mass of the ball

v = velocity of the ball

The distance that the platform moves is given by:

X = Vt ...eq2

Where t is the time that the ball is in the air.

The time the ball is in the air is given by:

L/(v-V) ...eq3

Where L is the length of the platform

The quantity(v-V) = velocity of the ball relative to the platform.

Combining eq2 and eq3

X = (V/(v - V))L

From eq1 , the ratios of the velocities is V/v = -m/M

X = (V/v)L / (1 - (V/v) = (-m/M) L /(1+ (m/M))

X = -mL/(M + m)

X = - (3.36kg × 3.12m) /( 119kg + 3.36kg)

X = - 10.48/ 122.36

X = -0.082m

The minus sign implies that the displacement of the platform is in the opposite direction to the displacement of the ball.

Therefore, the distance moved by the platform is the magnitude of this displacement 0.082m.

7 0
3 years ago
Read 2 more answers
Select the correct answer
Nadya [2.5K]

Answer:

f= 3.0 \times 10 {}^{8} \div 7.0 \times 10 {}^{7} \\ f = 4.28hz

Given

7 0
3 years ago
A 50.0 ohm and a 30.0 ohm resistor are connected in parallel. What is their equivalent resistance? Unit=Ohms
Alchen [17]

R(parallel) = product/ sum

50×30/50+30

1500/80

18,75 ohms

4 0
3 years ago
An 820 N Marine in basic training climbs a 12.0-m vertical rope at a constant speed in 8.00 s. What is her power output
sweet-ann [11.9K]

Answer:

1230 W

Explanation:

P = \frac{W}{t} = \frac{Force * distance}{time} = \frac{820 N * 12.0 m}{8.00 s} = 1230 Watts

6 0
3 years ago
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