Answer:
Speed of the bug is 0.0832 m/s.
Explanation:
We have,
Radius of the circular planet is 18.3 cm or 0.183 m and time taken by the bug to complete one lap is 13.81 s.
It is required to find the speed of the bug in the circular path. It is given by the displacement in one lap divided by time taken. So,
So, the speed of the bug is 0.0832 m/s.
As the external magnetic field decreases, an induced current flows in the coil. The direction of the induced magnetic field would be pointing to the screen. The flux through the coil is said to decrease. In order to counter this change, the coil would generate or produce a magnetic field that is induced that would be pointing to the same direction as the external field that is flowing which is into the the screen. This is according to Lenz's law or the right hand rule. It states that an induced current in a circuit that is due to the change or motion in magnetic field should be directed opposing to the change in the flux.
When its going from one medium to another.
Answer:
31.6 m/s
Explanation:
Mass is conserved, so the mass flow at the outlet of the pump equals the mass flow at the nozzle.
m₁ = m₂
ρQ₁ = ρQ₂
Q₁ = Q₂
v₁A₁ = v₂A₂
v₁ πd₁²/4 = v₂ πd₂²/4
v₁ d₁² = v₂ d₂²
Now use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Since h₁ = 0 and P₂ = 0:
P₁ + ½ ρ v₁² = ½ ρ v₂² + ρgh₂
Writing v₁ in terms of v₂:
P₁ + ½ ρ (v₂ d₂²/d₁²)² = ½ ρ v₂² + ρgh₂
P₁ + ½ ρ (d₂/d₁)⁴ v₂² = ½ ρ v₂² + ρgh₂
P₁ − ρgh₂ = ½ ρ (1 − (d₂/d₁)⁴) v₂²
Plugging in values:
579,160 Pa − (1000 kg/m³)(9.8 m/s²)(15 m) = ½ (1000 kg/m³) (1 − (1.99 in / 3.28 in)⁴) v₂²
v₂ = 31.6 m/s
