Answer:
calm down please its not that serious maybe no one saw it yet
Explanation:
Answer:
Option E is correct 310N
Explanation:
Given that the force used to push the crate is F = 200N
The force directed 20° below the horizontal
Mass of crate is m = 25kg
Weight of the crate can be determine using
W = mg
g is gravitational constant =9.8m/s²
W = 25×9.8
W = 245 N
Check attachment. For free body diagram and better understanding
Using newton second law along the vertical axis since we want to find the normal force
ΣFy = m•ay
ay = 0, since the body is not moving in the vertical or y direction
N—W—F•Sin20 = 0
N = W+F•Sin20
N = 245+ 200Sin20
N = 245 + 68.4
N = 313.4 N
The normal force is approximately 310 N to the nearest ten
Answer:
It includes earthwork, trenching, wall shafts, tunneling and underground
Explanation:
When the gold cube is immersed in mercury, the tension in the string in Newtons is 3.142N.
<h3>What is tension?</h3>
Tension is the force acting on the linear object like string, chain or rope due to pulling.
Volume of gold V = mass / density
V = 1.18 /19.3x 10³ =61.1 x 10⁻⁶ m³
Tension in the string after immersing will be
T = [ρ(Gold) -ρ(Hg)] g. V
T =[ 19.3x 10³ - 13.6 x 10³] x 9.81 x 61.1 x 10⁻⁶
T =3.416 N
Thus, the tension in the string is 3.42 N.
Learn more about tension.
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