Answer:
Option B
Lockout/ Tagout
Explanation:
lockout and tagout is a safety procedure used in most industries and work places. This ensures that during any maintenance work, that dangerous machines are properly shut off and not able to be started up again prior to the completion of maintenance or repair work.
The procedure includes:
1. Turns off and disconnects the machinery or equipment from its energy source(s) before performing service or maintenance.
2. The authorized employee(s) either lock or tag the energy-isolating device(s) to prevent the release of hazardous energy.
To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.
The gas ideal law is given as,

Where,
P = Pressure
V = Volume
m = mass
R = Gas Constant
T = Temperature
Our data are given by




Note that the pressure to 38°C is 0.06626 bar
PART A) Using the ideal gas equation to calculate the mass flow,




Therfore the mass flow rate at which water condenses, then

Re-arrange to find 



PART B) Enthalpy is given by definition as,

Where,
= Enthalpy of dry air
= Enthalpy of water vapor
Replacing with our values we have that



In the conversion system 1 ton is equal to 210kJ / min


The cooling requeriment in tons of cooling is 437.2.
Answer:
f(5)
Explanation:
Function notation is a precise way of giving information about a function without need for a lengthy written explanation. The most common function notation is f (x) which is interpreted as "f of x".
For the year 2005,
t = 2005 -2000
= 5
Using the function notation to represent the cost (in dollars) of a new Accord in 2005 is f(5)
Answer:
Mechanical power of pump is 74.07%.
Explanation:
Power of motor = 15 KW
Efficiency of motor= 90%
So the actual power(P) supplied by motor = 0.9 x 15 KW
P=13.5 KW
Water flow rate = 50 L/s
Volume flow rate = 50 L/s
We know that

So

We know that pump is an open system and work input for open system can be calculated as
W=VΔP
ΔP is the pressure difference
V is the volume flow rate
So by putting the values
W=0.05 (300-100) (here ΔP=300 - 100=200 KPa)
W=10 KW
So mechanical power of pump
η =0.7407
Mechanical power of pump is 74.07%.
Answer: Focusing on the road
Explanation:
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