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n200080 [17]
3 years ago
8

The 10th power of t

Mathematics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

t¹⁰

Step-by-step explanation:

The 10th power of t:

t¹⁰

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Give the center, radius, and equation of the circle in the graph.
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Answer:

(x-2)^2+(y+3)^2=4

Step-by-step explanation:

  • A circle's equation consist on the following expression: (x-a)^2+(y-b)^2=r^2, where r is the magnitude of the radio, and (a,b) are the coordenates of the center of the circle.
  • In this case, a=2 and b= - 3, because the circle is centered in (x,y)=(2, - 3).
  • The radio, which is the distance between the center of the radio to any point in its border, equals r=2 (because of the scale of the graphic, in this case two squares of the grid equal 2 units, then r=2).
  • Finally, using the previous information to replace in the equation (x-2)^2+(y+3)^2=4, where the fact that r=2 and 2^2=4 was used.
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All rectangles are _____.<br><br> parallelograms<br> rhombuses<br> squares<br> quadrilaterals
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Besides phone numbers, what are the other categorical variables in your survey? (The survey asks for family size, the kind of pe
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Step-by-step explanation:

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A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
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Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

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