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11Alexandr11 [23.1K]
3 years ago
14

Help Me ASAP! Looking at the picture above which images would be best classified as molecules?​

Chemistry
2 answers:
Goshia [24]3 years ago
3 0

Answer:

B

Explanation:

astra-53 [7]3 years ago
3 0

Answer:

C) B AND C

Explanation:

points

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The reaction of nitrogen dioxide with fluorine
andrew-mc [135]

Answer:

Rate = 0.001615 Ms-1

Explanation:

2 NO2 + F2 --> 2 NO2F

The reaction is first order with respect to NO2 and also first order with respect to F2.

The rate law is given as;

Rate = k [NO2] [ F2]

k = 1.58E-4 M-1s-1

[NO2] = 2.84 M

[F2] = 3.60 M

Rate = ?

Inserting the values into the equation, we have;

Rate = 1.58E-4 * 2.84 * 3.60

Rate = 0.001615 Ms-1

4 0
3 years ago
Which compares the problem associated with radioactive waste created from generating electricity using fusion reactions to waste
uysha [10]

Answer:

hello good person

Explanation:

8 0
3 years ago
The quantity 44 liters expressed in cubic meters is ____.
Lerok [7]

D. 0.044 m3

hope this helped

7 0
3 years ago
Silver and gold are both considered coinage metals. How does a mile of silver compare with a mole of iron ?
fomenos

Answer:

both have the same number of atoms

Explanation:

saw it on a quizlet

7 0
3 years ago
1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is
earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

\frac{6}{80}=\frac{V_{2} }{40}

V_{2}=\frac{6*40}{80}=3 L

So, 3 L will be the final volume for the gas as per Charle's law.

4 0
3 years ago
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