Answer:
c. ![\frac{1}{12n} = {[12n]}^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12n%7D%20%3D%20%7B%5B12n%5D%7D%5E%7B-1%7D)
Step-by-step explanation:
![[\frac{1}{4}][\frac{2}{5}][\frac{1}{2}][\frac{4}{7}][\frac{5}{8}][\frac{2}{3}][\frac{7}{n}] = \frac{560}{6720n} = [12n]^{-1} = \frac{1}{12n}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B4%7D%5D%5B%5Cfrac%7B2%7D%7B5%7D%5D%5B%5Cfrac%7B1%7D%7B2%7D%5D%5B%5Cfrac%7B4%7D%7B7%7D%5D%5B%5Cfrac%7B5%7D%7B8%7D%5D%5B%5Cfrac%7B2%7D%7B3%7D%5D%5B%5Cfrac%7B7%7D%7Bn%7D%5D%20%3D%20%5Cfrac%7B560%7D%7B6720n%7D%20%3D%20%5B12n%5D%5E%7B-1%7D%20%3D%20%5Cfrac%7B1%7D%7B12n%7D)
* To make this simpler, reduce these two fractions in lowest terms.
I am joyous to assist you anytime.
Answer:
Rules for Reflections
Step-by-step explanation:
hope this helps :)
The answer for this problem is 26.
Answer:
Area = 7.853981 in^2 (2.5 Pi)
Perimeter = 11.42478 in (3.63Pi)
Step-by-step explanation:
Area
Lg semi circle area = Pi(2^2)(0.5) = 3.141593(4)0.5) = 6.283185 in^2
Sm semi circle area = Pi(1^2)(0.5) = 3.141593(2)(0.5) = 1.570796 in^2
added together = 7.853981 in^2
Perimeter
Lg semi circle perimeter = Pi(4)(0.5) + 2 = 8.283185 in
Sm semi circle perimeter = Pi(2)(0.5) = 3.141593 in
added together = 11.42478 in
When put into standard form, the equation turns out like this:
-2m^4-6m^2+4m+9
