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Lina20 [59]
3 years ago
8

If I have a 50 liter container that holds 45 moles of gas at a temperature of 200 0C, what is the pressure inside the container?

Chemistry
1 answer:
Bezzdna [24]3 years ago
8 0

hdhjdbdhjssnmsmsnsjsbxbhow?

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Coal is burned in the atmosphere to release energy. Which gas is needed for burning to take place?
irga5000 [103]

Answer:

Oxygen gas is needed for burning to take place.

Explanation:

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Chlorine has 7 valence electrons. Hydrogen has 1 valence
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B.1 Chlorine wants 8 Hydrogen has one to give 7 plus on is 8
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Given that ΔH = −571.6 kJ/mol for the reaction 2 H2(g) + O2(g) → 2 H2O(l), calculate ΔH for these reactions. (a) 2 H2O(l) → 2 H2
pashok25 [27]

Answer : The value of \Delta H for the reaction is +571.6 kJ/mole.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)     \Delta H_1=-571.6kJ/mole

Now we have to determine the value of \Delta H for the following reaction i.e,

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)    \Delta H_2=?

According to the Hess’s law, if we reverse the reaction then the sign of \Delta H change.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=-(-571.6kJ/mole)

\Delta H_2=+571.6kJ/mole

Hence, the value of \Delta H for the reaction is +571.6 kJ/mole.

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3 years ago
What is pseudo - order reaction​
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Explanation:

The reactions which are not truly of first order but become reactions of first order under certain conditions are called pseudo first order reactions.

For example, hydrolysis of ester

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How many grams of NaOH are produced from 20 grams of Na2Co3
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Answer:

1400

Explanation:

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