Answer:
Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.
Explanation:
I just took the test and i got it right
Answer:
The Flow rate = 0.0208 mL/min
Explanation:
Data provided:
Rate of dose = 39 mg every 30 min = (39/30) mg/min = 1.3 mg/min
also,
125mg of methylprednisolone is present in every 2 mL
thus,
concentration = (125/2) mg/mL = 62.5 mg/mL
Now,
The flow rate is given as:
Flow rate = Rate / Concentration
on substituting the respective values, we get
Flow rate = (1.3 mg/min) / (62.5mg/mL)
or
The Flow rate = 0.0208 mL/min
Answer:
a price war
Explanation:
An Oligopoly is when a small group of two or more companies dominates a market. Oligopoly firms may consent to market collusion, and create barriers to new commerce entry. If the businesses do not, they will probably be forced to lower their prices and open the market to new and smaller companies.
It is the type of competition between the company selling the similar type of product , or rival companies who tries to reduce the price of the product strategizing in a way to apprehend the wider area of the market , is known as a price war .
In the event one of the firms forming the oligopoly decides to lower prices, a price war occurs breaking the balance of the oligopoly and destabilizing the equilibrium of demand and supply in that market.
Reduction of the price of any goods or commodity is considered to be one of the best method to increase its market share ,because as soon as the price of any good decreases , the sales automatically increases , as the consumers are always in search of some discounts and good deals .
price war -
Answer:
The moon to the direct right of the Earth relative to the Sun
Explanation:
Oxidation is the loss of electrons and corresponds to an increase in oxidation state. Reduction is the gain of electrons and corresponds to a decrease in oxidation state. Balancing redox reactions can be more complicated than balancing other types of reactions because both the mass and charge must be balanced. Redox reactions occurring in aqueous solutions can be balanced by using a special procedure called the half-reaction method of balancing. In this procedure the overall equation is broken down into two half-reactions: one for oxidation and the other for reduction. The half-reactions are balanced individually and then added together so that the number of electrons generated in the oxidation half reaction is the same as the number of electrons consumed in the reduction half-reaction.
