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2 years ago

What is the density (g/L) of 5.0 moles of NH3, at 1.18 atm and 25.0°C?

Chemistry

2 answers:

Goryan [66]2 years ago

5 0

The answer will be 4667C

tatuchka [14]2 years ago

4 0

Answer:

.821 g/L

Explanation:

It does not matter what the gas is, just the number of moles to calculate volume....

Ideal Gas Law :

PV = n R T R = gas constant = .082057 L-atm/(mol-K) & T in Kelvin units

(1.18)(V) = 5 * .082057 * (25 + 273.15)

V = 103.67 Liters

NOW ...to calculate density, the gas IS important...

mole weight of NH3 (from periodic table) = 17.031 gm/mole

Density = mass / volume = (5 * 17.031) / 103.67 L = .821 gm/L

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Suppose now that you wanted to determine the density of a small crystal to confirm that it is graphite. From the literature, you

kirza4 [7]

Answer:

The volume of first and second compound are 9.15 ml and 10.85 ml.

Explanation:

Given that,

Density of graphite = 2.25 g/cm³

Volume of mixture = 20.0 mL

Density of first compound = 1.492 g/ml

Density of second compound = 2.890 g/ml

Let the volume of first mixture = x

The volume of second mixture = (20-x)....(I)

We need to calculate the volume of first compound

Using formula of density of mixture

$\rho=\dfrac{V_{1}\rho_{1}+V_{2}\rho_{2}}{V_{1}+V_{2}}$

Where, $V_{1}$ = volume of first compound

$V_{2}$ = volume of second compound

$\rho_{1}$ =density of first compound

$\rho_{1}$ = density of first compound

Put the volume into the formula

$2.25=\dfrac{x\times1.492+(20-x)\times2.890}{x+20-x}$

$45=1.492x+57.8-2.890x$

$45-57.8=1.492x-2.890x$

$12.8=1.398x$

$x=\dfrac{12.8}{1.398}$

$x=9.15\ ml$

We need to calculate the volume of second compound

Using equation (I)

$V_{2}=20-x$

Put the value of x

$V_{2}=20-9.15$

$V_{2}=10.85\ ml$

Hence, The volume of first and second compound are 9.15 ml and 10.85 ml.

5 0

3 years ago

WILL GIVE NRAINLIEST!! NEED HELP FAST

Elis [28]

Hello,

I believe this is (25 g Al) * (1 mol H / 1.008 g H) = 24.8015 mol H

Hopefully that was the right approach.
I thought that if one mole of Al is
26.982 g, then the numbers of moles for H (1.008 g/mol) would be about 25 mol.
If it doesn’t make sense or if you have resources/notes to which I can refer, I’ll see what I can do!

Good luck!

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3 years ago

Plz help!!! This is timed!!!

pogonyaev

58.7 %

Please correct me if I’m wrong. :)

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kvasek [131]

Answer:

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vazorg [7]

Answer

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