1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rufina [12.5K]
3 years ago
7

in a typical person, the level of glucose is about 85 mg/ 100 mL of blood. if an average body contains about 11 pt of blood, how

many grams and how many pounds of glucose are present in the blood?
Chemistry
1 answer:
Vanyuwa [196]3 years ago
5 0

Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.

We make a proportion out of the word problem

(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose

You might be interested in
The measured value 24.00 g has an uncertainty of?
Orlov [11]

Answer:

±0.005 g

Explanation:

The uncertainty depends on whether the measurement was obtained manually or digitally.

1. Manual

The minimum uncertainty is ±0.01 g.

It may be greater, depending on random or personal errors

2. Digital

Most measurements of mass are now made on digital scales.

A digital device must always round off the measurement it displays.

For example, if the display reads 20.00, the measurement must be between 20.005 and 19.995 (±0.005).

If the measured value were 20.006, the display would round up to 20.01.

If the measured value were 19.994, the display would round down to 19.99.

The uncertainty is ±0.005 g.

The scale shown below would display a mass of 20.00 g

6 0
3 years ago
What mass of CO was used up in the reaction with an excess of oxygen gas if 24.7g of carbon dioxide is formed? 2 CO + O2 > 2
Zolol [24]
Balance Chemical Equation,
                                      2 CO  +  O₂   →   2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when  =  56 g (2 mole)of CO was reacted
So, 
24.7 g of CO₂ will be produced by reacting =  X g of CO

Solving for X,
                                    X  =  (56 g × 24.7 g) ÷ 88 g

                                    X  =  2.26 g ÷ 88 g

                                    X  =  0.0257 g of CO

Result:           
            0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
7 0
3 years ago
A baseball strikes the roof of a car and dents it. The paint on the roof begins to crack and chip, exposing the metal. The expos
s2008m [1.1K]

Answer:

The exposed metal rusts is an example of a chemical change because rust is an example of a chemical change in objects for example bicycles, scooters, etc.

4 0
3 years ago
Read 2 more answers
a heliox tank contains 32% helium and 68% oxygen. the total pressure in the tank is 395 kPa. What is the partial pressure of oxy
trapecia [35]

Answer:

Pp O2 = 82.944 KPa

Explanation:

heliox tank:

∴ %wt He = 32%

∴ %wt O2 = 68%

∴ Pt = 395 KPa

⇒ Pp O2 = ?

assuming a mix of ideal gases at the temperature and volumen of the mix:

∴ Pi = RTni/V

∴ Pt = RTnt/V

⇒ Pi/Pt = ni/nt = Xi

⇒ Pi = (Xi)*(Pt)

∴ Xi: molar fraction (ni/nt)

⇒ 0.68 = mass O2/mass mix

assuming mass mix = 100 g

⇒ mass O2 = 68 g

∴ molar mass O2 = 32 g/mol

⇒ moles O2 = (68 g)(mol/32 g) = 2.125 mol O2

⇒ mass He = 32 g

∴ molar mass He = 4.0026 g/mol

⇒ moles He = (32 g)(mol/4.0026 g) = 7.995 mol He

⇒ nt = nO2 + nHe = 2.125 mol + 7.995 mol = 10.12 moles

molar fraction O2:

⇒ X O2 = nO2/nt = (2.125 mol/10.12 mol) = 0.2099

⇒ Pp O2 = (X O2)(Pt)

⇒ Pp O2 = (0.2099)(395 KPa)

⇒ Pp O2 = 82.944 KPa

6 0
3 years ago
The heat capacity of liquid water is 4.18 J/g·°C and the heat of vaporization is 40.7 kJ/mol. How many kilojoules of heat must b
pychu [463]

Answer:

The correct answer would be - 2.4KJ or, 2400J

Explanation:

Given:

heat capacity of liquid water - 4.18 J/g·°C

heat of vaporization - 40.7 kJ/mol

Mass of water = 1g

Moles of water = mass/molar mass

= 1g/18.016g

= 0.055 moles

Then,

Total heat required = q1(to raise the temperature to 100) + q2(change from the liquid phase to gas/steam)

= m *s*dt + moles * heat of vaporization

= (1g * 4.18 j/gc * (100-67)) + 0.055* 40.7 KJ

= 137.94J + 2.26KJ

=0.138KJ + 2.26KJ

=2.4KJ or, 2400J

Thus, the correct answer would be - 2.4KJ or, 2400J

3 0
3 years ago
Other questions:
  • how many moles of CO2 form when 58.0 g of butane, C4H10, burn in oxygen? 2C4H10+13O2--->8CO2+10H2O
    9·2 answers
  • How might you tell if a food contains an acid as one of its ingredients?
    14·2 answers
  • When magnesium metal is heated in air it begins to release large amounts of heat and light. What kind of a reaction is this an e
    12·2 answers
  • Materials of low mass are combined to form a substance of higher mass during ____. a. fission c. both A and B b. fusion d. neith
    14·1 answer
  • Is a molecule positive or negative?
    13·1 answer
  • The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v).
    10·2 answers
  • वर्षा के तीन पृकार लिखिए<br>​
    6·1 answer
  • Water conservation is important for which of the following reasons?
    15·2 answers
  • Define acidic salt with example​
    14·2 answers
  • 1) A potassium carbonate hydrate has a formula K2CO3.XH2O. 10g of the hydrate leave 7.83g of anhydrous salt upon heating. Deduce
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!