Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.
We make a proportion out of the word problem
(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose
Explanation:
To balance this chemical equation-
see
Balanced form:-
CaO + 2 HCl ==. CaCl2 + H2O
.
Answer:
Yes.