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2 years ago

What is the mass of oxygen gas in a 12.2 L

Chemistry

1 answer:

baherus [9]2 years ago

4 0

Answer:

grams O₂ = 134 grams

Explanation:

PV = nRT => n = PV/RT

P = 8.15atm

V = 12.2 Liters

R = 0.08206L·atm/mol·K

T = 16.0°C + 273 = 289K

n = (8.15atm)(12.2L)/(0.08206L·atm/mol·K)(289K) = 4.2 moles O₂

grams O₂ = 4.2 moles O₂ x 32g/mol = 134 grams O₂

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how many grams of phosphorus (P4) react with 35.5L of O2 at STP to form solid tetraphosphorus decaoxide

algol [13]

Answer:

mass P4 = 35.998 g

Explanation:

P4 + 5O2 → P4O10

∴ STP: P = 1 atm; T = 298 K

∴ V O2= 35.5 L

⇒ nO2 = P.V / R.T

∴ R = 0.082 atm.L/K.mol

⇒ nO2 = ((1 atm)×(35.5L))/((0.082 atm.L/K.mol)(298K))

⇒ nO2 = 1.453 mol O2

⇒ mol P4 = (1.453 molO2)×(mol P4/ 5molO2) = 0.2906 mol P4

∴ Mw P4 = 123.895 g/mol

⇒ mass P4 = (0.2906 mol P4)×(123.895 g/mol) = 35.998 g P4

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3 years ago

How does the law of conservation of mass apply to this reaction: Mg + HCl → H2 + MgCl2?

erastova [34]

Answer: The correct answer is A. Hydrogen and chlorine need to be balanced. There's an equal amount of magnesium on each side.

6 0

3 years ago

Read 2 more answers

The area of a telescope lens is 7903 rnrn2 {a) What is the area in square feet (ft2)? (b) If it takes a technician 45 s to polis

LekaFEV [45]

Answer:

Area is 0.08504 $ft^{2}$ and $2.6\times 10^{3}s$ are needed for polishing

Explanation:

(a) ft is unit of F.P.S system whether mm is unit of M.K.S system.

According to unit conversion, $1mm=0.00328ft$

So, $1mm^{2}=(0.00328)^{2}ft^{2}=1.076\times 10^{-5}ft^{2}$

hence, $7903mm^{2}=7903\times 1.076\times 10^{-5}ft^{2}=0.08504ft^{2}$

So, area of telescope lens is 0.08504 $ft^{2}$

(b) $135mm^{2}$ are polished in 45s

So, $7903mm^{2}$ are polished in $\frac{45\times 7903}{135}s$ or $2.6\times 10^{3}s$

5 0

2 years ago

Chemistry help!! I'll give 30 points!!!

malfutka [58]

1. 1/16 x 1 000 000= 62500
2. Each half life is 5750 years long
3. The end of a half life is found by dividing the beginning of the half life by 2.
4. The number 62500 is between the 7th and the 8th half lives (refer to the number of 14C atoms on my table)
5. The 7th half life is 40250 years, and the 8th half life is 46000 years.
6. Therefore, your estimate would be a number roughly in the middle of 40250 and 46000 (for example: 43000)
Hope this helps :)

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3 years ago

What does the enthalpy of reaction measure?

Gnesinka [82]

The heat released/absorbed by a reaction that occurs at constant pressure.

Hope this helped :)

7 0

3 years ago

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