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2 years ago

What is the mass of oxygen gas in a 12.2 L

Chemistry

1 answer:

baherus [9]2 years ago

4 0

Answer:

grams O₂ = 134 grams

Explanation:

PV = nRT => n = PV/RT

P = 8.15atm

V = 12.2 Liters

R = 0.08206L·atm/mol·K

T = 16.0°C + 273 = 289K

n = (8.15atm)(12.2L)/(0.08206L·atm/mol·K)(289K) = 4.2 moles O₂

grams O₂ = 4.2 moles O₂ x 32g/mol = 134 grams O₂

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The chemical formula for beryllium oxide is BeO.A chemist determined by measurements that 0.045 moles of beryllium participated

blondinia [14]

Answer: 0.405g

Explanation:

Molar Mass of Be = 9g/mol

Number of mole of Be = 0.045mol

Mass conc. Of Be = 0.045 x 9 = 0.405g

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3 years ago

NEED HELP QUICKLY!!! How many moles are in each of the following?

oksano4ka [1.4K]

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3 years ago

Which of these best describes Earth’s core?

Monica [59]

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3 years ago

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kifflom [539]

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2 years ago

What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M

Fed [463]

36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.

What is benzoic acid found in?

Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 = 0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

$pH = pKa + log\frac{base}{acid}$