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aivan3 [116]
2 years ago
5

What is the mass of oxygen gas in a 12.2 L

Chemistry
1 answer:
baherus [9]2 years ago
4 0

Answer:

grams O₂ = 134 grams

Explanation:

PV = nRT => n = PV/RT

P = 8.15atm

V = 12.2 Liters

R = 0.08206L·atm/mol·K

T = 16.0°C + 273 = 289K

n = (8.15atm)(12.2L)/(0.08206L·atm/mol·K)(289K) = 4.2 moles O₂

grams O₂ = 4.2 moles O₂ x 32g/mol = 134 grams O₂

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The heat lost by copper(ii) sulfate is equal to heat absorbed by water since the total energy in the system remains constant according to the law of conservation of energy.

<h3>How can the number of moles be determined?</h3>

The number of moles of a substance is determined using the formula below:

  • Number of moles = mass/molar mass

Assuming the mass of copper(ii) sulfate used is <em>Mc</em>, number of moles of copper(ii) sulfate used is:

  • Moles of copper(ii) sulfate = <em>Mc</em>/159.60 moles

The heat absorbed by water is calculated using the formula below:

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mass of water <em>=</em><em> </em> 10 g

Let temperature change be <em>Tc</em>

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86Tc

The change in internal energy, ΔU of copper(ii) sulfate, is given as:

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Q =  heat absorbed by water

W  =  work done by or on the system

The enthalpy of the reaction is given as:

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Therefore, according to the law of conservation of energy, the total energy in the system remains constant.

Learn more about internal energy change at: brainly.com/question/14126477

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