The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.
Given:
The nitrogen gas molecule with a temperature of 330 Kelvins is released from Earth's surface to travel upward.
To find:
The maximum height of a nitrogen molecule when released from the Earth's surface before coming to rest.
Solution:
- The maximum height attained by nitrogen gas molecule = h
- The temperature of nitrogen gas particle = T = 330 K
The average kinetic energy of the gas particles is given by:

The nitrogen molecule at its maximum height will have zero kinetic energy as all the kinetic energy will get converted into potential energy
- The potential energy at height h =

- Molar mass of nitrogen gas = 28.0134 g/mol
- Mass of nitrogen gas molecule = m

- The acceleration due to gravity = g = 9.8 m/s^2
- The maximum height attained by nitrogen gas molecule = h
- The potential energy is given by:


The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.
Learn more about the average kinetic energy of gas particles here:
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Answer:
It was done correctly, Your answer is completely correct.
Explanation:
Answer:
Higher concentration to an area of lower concentration
Explanation:
When you open a perfume bottle at a corner of a room, after a while, its fragrance can be perceived across a distance at the other end of the room. This is because, molecules of the compound in the fragrance have moved from the area of higher concentration in the perfume bottle, across a concentration gradient to a region of lower concentration at the other end of the room. This is diffusion.
Jeez this is middle school really. covalently bond
Answer:
2584 g
Explanation:
The molecular formula for sucrose is C₁₂H₂₂O₁₁, which means its molar mass is 342.3 g/mol.
First we<u> convert molecules into moles</u> by using <em>Avogadro's number</em>:
- 4.55x10²⁴ molecules ÷ 6.023x10²³ mol/molecules = 7.55 mol
Now we <u>convert moles of sucrose into grams</u>, using its<em> molar mass</em>:
- 7.55 mol * 342.3 g/mol = 2584 g