Answer:
Gamma radiation or Cathode rays
Explanation:
by striking incident gamma or cathode rays onto the solid when placed on a photographic plate
________b_____ 7 km east
|
| 2km north.
|a
|
°
pythagorean theorem : ✓a² + b² = c²
c² = a² + b² = 4 + 49 = 53
c = ✓53 km
displacement = c = ✓53 km
distance = 10 + 3 + 2 = 15 km
Solution:
We have,
Power [P] = 25000 Watt
Mass [m] = 6000 kg
Height [h] = 20 metres
Time [t] = ?
Now,
P = W/t = F x d/t = mxgx h/t
Or, 25000 = 6000 x 10 x 20/25000 [.......g = 10
m/s^2]
Or, t = 6000 x 10 x 20/25000
Or, t = 1200/25
Therefore, t = 48 second
Hence, the required time for the crane to lift the load is 48 seconds.
The body moves at a velocity of 1.62m/s after the bullet emerges.
<h3>Given:</h3>
Mass of bullet, = 22g
= 0.022 kg
Mass of the block, = 1.9 kg
Velocity of bullet , = 265 m/s
According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
After penetration;
The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
∴ Momentum before = Momentum after
Substitute the given parameters into the formula as shown:
Therefore, It moves with a velocity of 1.62 m/s.
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The average velocity of the lizard for the whole journey is 0.26 m/s Down.
<h3>What is average velocity?</h3>
The term average velocity has to do with the velocity of the lizard for the whole journey. We can see that the downward displacement is greater than the upward displacement.
Thus;
Velocity = displacement / time = 23.7 m - 15.5 m/31.5s = 0.26 m/s Down.
Thus, the average velocity of the lizard for the whole journey is 0.26 m/s Down.
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