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mario62 [17]
2 years ago
15

Help my cat is constipated what do I do

Physics
1 answer:
storchak [24]2 years ago
7 0

Answer:

Increase Water Consumption

Try a New Diet

Help Your Cat Maintain a Healthy Weight

Increase Exercise and Enrichment

Minimize Stress and Anxiety

Add More Litter Boxes

Try Fiber or Probiotics

Ask Your Vet About Over-the-Counter Laxatives

Explanation:

<h2><em>Hope this helps ;)</em></h2>

<em></em>

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You are an astronomer and are making observations about a visible but faraway galaxy. Describe what evidence you could gather to
Pavel [41]

Answer:

Chemical Composition

The chemical composition of the Universe is dominated by the hydrogen and helium produced in the Big Bang. The remaining 90 or so chemical elements are produced in stars and constitute only a few percent of the overall mass. Astronomers refer to these elements (all except hydrogen and helium) as metals, even though this includes elements such as carbon and oxygen which are not considered metals in the normal sense.

The abundance of metals with respect to hydrogen is known as the metallicity. While hydrogen and helium are found in high abundance throughout the Universe, the metallicity varies depending on the history of star formation in the region. The chemical composition of the Sun gives us some idea of the chemical composition of the solar neighbourhood:

Chemical composition of the Sun

Hydrogen 73%

Helium 25%

Oxygen 0.80%

Carbon 0.36%

Iron 0.16%

Neon 0.12%

Nitrogen 0.09%

Silicon 0.07%

Magnesium 0.05%

Sulphur 0.04%

Others combined 0.04%

This indicates that metals constitute only about 2% of the Sun’s mass.

The highest metallicities are found in the centres of galaxies. For example, near the centre of the Milky Way, stars with metallicities of up to three times the solar value have been observed. However, there are also stars with only 1/10,000th of the solar value. These stars formed early in the history of the Galaxy, before the interstellar medium (and subsequent generations of stars) became enriched in metals through the actions of other stars.

Although never more than a few percent by mass, the metals content of stars has a significant effect on their stellar evolution, with metal-rich stars being cooler, larger and longer-lived than metal-poor stars of the same mass. Both the length of time spent on the main sequence and the detail of post-main sequence evolution are significantly affected by a star’s metallicity.

To fully describe the chemical composition of stars (or galaxies) it is also necessary to define abundance ratios. These relate the relative abundances of metals to each other (e.g. the abundance ratio of magnesium to iron or carbon to oxygen). Astronomers use these abundance ratios to measure how long the object in question has been forming stars.

Both metallicities and abundance ratios are usually expressed in terms of the values for the Sun, and normally on a logarithmic scale.

6 0
2 years ago
Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collid
jarptica [38.1K]

Answer:

Explanation:

Using the law of conservation of momentum;

m_1 u_1+m_2u_2 = m_1v_1+m_2v_2

here;

There is a need for conservation of the total momentum that occurred before and after the collision.

So;

m_1 = mass of cart X

m_2 = mas 9f cart Y

u_1 = velocity of cart X (before collision)

u_2 = velocity of cart Y (before collision)

v_1 = velocity of cart X (after collision)

v_2 = velocity of cart Y (after collision)

So;

m(u_1+0) =(m_1v+m_2)v

because the mass is identical and v represents the velocity of both carts.

Now;

u_1 = 2 m/s

u_2 = 0 ( at rest)

∴

m(2) = (2m)v

v = 1 m/s

Thus, we can see from the graphical image attached below that the velocity of X reduces to 1 m/s after collision with cart Y.

8 0
3 years ago
În ce raport de mase trebuie amestecate două cantități din același lichid, având temperaturile t1=10 grade Celsius, respectiv t2
Brilliant_brown [7]

Răspuns:

7: 4

Explicaţie:

Formula pentru calcularea cantității de căldură absorbită este exprimată ca;

Q = mc∆t

m este masa substanței

c este capacitatea termică specifică

∆t este schimbarea temperaturii

Conform legii calorimetriei, căldura pierdută de substanța rece = căldura câștigată de substanța fierbinte.

Folosind formula

(mc∆t) rece = (mc∆t) fierbinte

McCw∆tc = MhCw∆th

Deoarece au aceeași capacitate de căldură specifică, se vor anula. Ecuația devine;

Mc∆tc = Mh∆th ...... 1

Pentru apa rece;

∆tc = 45 ° C - 10 ° C

∆tc = 35 ° C

Pentru apa fierbinte:

∆th = 65 ° C - 45 ° C

∆th = 20 ° C

Înlocuiți în ecuația 1;

Mc (35) = Mh (20)

35Mc = 20Mh

Luând raportul dintre masa apei reci și cea fierbinte:

Mh / Mc = 35/20

Mh / Mc = 7/4

Prin urmare, lichidul trebuie amestecat împreună în raportul 7: 4

8 0
3 years ago
A leopard of mass 65kg climbs 7m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g=10N/kg.
vesna_86 [32]

Answer: 4550 Joules

The formula for potential energy in gravitational field is as follows:

E_{pot} = mgh=65kg \cdot 10 \frac{N}{kg} \cdot 7m = 4550 J

8 0
3 years ago
What is the change in potential energy of an energetic 72 kg hiker who makes it from the floor of death valley to the top of mt.
storchak [24]
<span>The lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m. </span>
3 0
3 years ago
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