Answer:
Population I stars are usually the blue younger stars. They orbit in the disk and they are relatively rich in metals. Population II stars are the red, older stars that lies in the bulge and halo of the Galaxy. They orbits in the elliptical orbits in the halo.
Population I stars include the sun and tend to be luminous, hot and young, concentrated in the disks of spiral galaxies. They are particularly found in the spiral arms. while, Population II stars tend to be found in globular clusters and the nucleus of a galaxy. They tend to be older, less luminous and cooler than Population I stars. They have fewer heavy elements.
D.) A molecule of glucose,
Kinetic energy denotes movement, no movement no kinetic energy.
Answer:
79.1°
Explanation:
Given:
x₀ = 0 m
y₀ = 0 m
x = 19500 cos 32°
y = 19500 sin 32°
v₀x = 1810 cos 20°
v₀y = 1810 sin 20°
t = 9.20
Find:
ax, ay, θ
First, in the x direction:
x = x₀ + v₀ t + ½ at²
19500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²
16537 = 15648 + 42.32 ax
ax ≈ 21.01
And in the y direction:
y = y₀ + v₀ t + ½ at²
19500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²
10333 = 5695 + 42.32 ay
ay ≈ 109.6
The direction of the acceleration is therefore:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ ≈ 79.1°
Answer:
We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.
Explanation:
Given
To determine
Kinetic Energy (K.E) = ?
We know that a body can possess energy due to its movement — Kinetic Energy.
Kinetic Energy (K.E) can be determined using the formula
where
- K.E is the Kinetic Energy (J)
now substituting m = 1.75, and v = 54 in the formula
J
Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.
Answer:
They can be relied upon to produce the same traits generation after generation
Explanation:
