Question

What is the vertex of the graph of y = −1(x − 2)2 + 3? (3,-2) (-2,3) (3,2) (2,3)

Answer 1

The vertex form is y=a(x-h)²+k
the vertex is (h,k)
so

y=-1(x-2)²+3
compare to
y=a(x-h)²+k
2=h and 3=k
the vertex is  (2,3)
4th option

Answer 2

Answer:

(2,3)

Step-by-step explanation:

An equation of the form

$a^{2} + bx + c = 0$

can be expressed in the Vertex Form:

$y = a (x - h)^{2} + k$

where the vertex is always:

(h, k)

The vertex is the lowest or highest point of the parabola.

When we compare the two functions:

$y = a (x - h)^{2} + k$

$y = -1 (x - 2)^{2} + 3$

We can see that

a = -1

h = 2

k = 3

So the vertex is:

(h, k) = (2, 3)

I hope this helps!