Ask question

Ask question

All categories

3 years ago

9

Help I will be marking brainliest!!!

2 answers:

IRISSAK [1]3 years ago

3 0

Answer:

im not good with trigangles but illtry to help

Step-by-step explanation:

Anni [7]3 years ago

3 0

Answer:

Step-by-step explanation:

$sin60=\frac{HR}{72}\\ \\ HR=72sin60\\ \\ \text{They are checking to see if you know the relationships of the 30,60,90 triangle whos sides opposite of those angles are }1,\sqrt{3},2\\ \\ sin60=\frac{\sqrt{3}}{2}\\ \\ HR=\frac{72\sqrt{3}}{2}\\ \\HR=36\sqrt{3}$

You might be interested in

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

1. Name of the missing segment.<br> 2.Length of the missing segment.

allochka39001 [22]

Answer:

Name: FE

Length: 13

Step-by-step explanation:

The total length is 34, so you would do 34-21, which equals 13.

6 0

3 years ago

Read 2 more answers

Mar in was a bat and hit 7 out 8 balls. How can you find his batting precentage

777dan777 [17]

Divide 7 by 8 then multiply what you get by 100.

7 0

3 years ago

Read 2 more answers

What is the solution for the system of equations {9x+8y=3 6x−12y=−11?

lions [1.4K]

Answer:

( - $\frac{1}{3}$ , $\frac{3}{4}$ )

Step-by-step explanation:

Given the 2 equations

9x + 8y = 3 → (1)

6x - 12y = - 11 → (2)

To eliminate the y- term multiply (1) by 1.5

13.5x + 12y = 4.5 → (3)

Add (2) and (3) term by term

(6x + 13.5x) + (- 12y + 12y) = (- 11 + 4.5)

19.5x = - 6.5 ( divide both sides by 19.5 )

x = $\frac{-6.5}{19.5}$ = - $\frac{1}{3}$

Substitute this value into either of the 2 equations and solve for y

Using (1), then

- 3 + 8y = 3 ( add 3 to both sides )

8y = 6 ( divide both sides by 8 )

y = $\frac{6}{8}$ = $\frac{3}{4}$

Solution is (- $\frac{1}{3}$ , $\frac{3}{4}$ )

6 0

3 years ago

Please help solve this with working out :)

Anastaziya [24]

I hope this can help u

3 0

3 years ago