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DanielleElmas [232]
2 years ago
6

The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity betwee

n t1 = 1.0s and t2 = 4.0s.​
Physics
1 answer:
aniked [119]2 years ago
5 0

Answer: 15m/s

Explanation: <u>Average</u> <u>Velocity</u> is vector describing the total displacement of an object and the time taken to change its position. It is represented as:

v=\frac{\Delta x}{\Delta t}

At t₁ = 1.0s, displacement x₁ is:

x(1)=25+3(1)^{2}

x(1) = 28

At t₂ = 4.0s:

x(4)=25+3(4)^{2}

x(4) = 73

Then, average speed is

v=\frac{73-28}{4-1}

v = 15

The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s

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