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blagie [28]
3 years ago
14

The speed of sound in water is 1498 m/s. A sonar signal is sent straight down from a ship at a point just below the water surfac

e, and 1.75 s later, the reflected signal is detected. How deep is the water
Physics
1 answer:
olga2289 [7]3 years ago
8 0

Answer:

The water is 1310.75 meters deep.

Explanation:

The question gives us the speed of sound and the time the sonar signal takes to travel to the bottom of the water and back.

To find out the distance, we should first divide the time in half, so we only consider the time taken for the sound to reach the bottom of the water body.

This means:

Time = 1.75 / 2 = 0.875 seconds

The distance traveled in this time is:

Distance = Speed * Time

Distance = 1498 * 0.875

Distance = 1310.75 meters    

Thus, the water is 1310.75 meters deep.

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Describe the relationship between the Law of Conservation of Matter and balancing equations.
Yuliya22 [10]

Answer:

The mass of the products and reactants are the same on both sides of the equation.

The number of atoms of products and reactants are equal and hence it proves the law of conservation of mass.

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3 0
2 years ago
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Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t
Nezavi [6.7K]

Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

calculation of RT equivalent resistance

is:  

RT = R1 + R2 + R3

We replace the data of the statement in the previous expression and it remains:  

5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

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2 years ago
A newspaper and a metal lunchbox are sitting in sun. Why does metal lunchbox feel hotter to touch than a newspaper?
Thepotemich [5.8K]

Answer:

A

Explanation:

the metal lunchbox has a higher conductivity

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3 0
3 years ago
Earth's subsystems are the geosphere, atmosphere, hydrosphere, and biosphere. Energy and matter are transferred when Earth's sub
Leona [35]

Answer:

ok

Explanation:

The Earth is made of several subsystems or "spheres" that interact to form a complex and continuously changing whole called the Earth system. Scale

Processes operating in the Earth system take place on spatial scales varying from fractions of millimeters to thousands of kilometers, and on time scales that range from milliseconds to billions of years.

Examples of instantaneous - breathing; rotation of the Earth; earthquake

Examples of long term - making coal; plate tectonics

Cycles

The Earth system is characterized by numerous overlapping cycles in which matter is recycled over and over again. Cycles involve multiple spheres and systems interactions.

Examples of cycles: day and night; rock cycle; seasons

Energy

The Earth system is powered by energy from two major sources: the Sun and the planet's internal heat.

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6 0
2 years ago
4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of
Vesnalui [34]

Answer:

15.07 ksi

Explanation:

Given that:

Pitch (P) = 5 teeth/in

Pressure angle (\Phi) = 20°

Pinion speed (n_p ) = 2000 rev/min

Power (H) = 30 hp

Teeth on gear (N_G) = 50

Teeth on pinion (N_p) = 20

Face width (F) = 1 in

Let us first determine the diameter (d) of the pinion.

Diameter (d) = \frac{N}{P}

=\frac{20}{5}

= 4 in

From the values of Lewis Form Factor Y for (n_p ) = 20 ; at 20°

Y = 0.321

To find the velocity (V); we use the formula:

V = \frac{\pi d n_p}{12}

V = \frac{\pi *4*2000}{12}

V = 2094.40 ft/min

For cut or milled profile; the velocity factor (K_v) can be determined as follows:

K_v = \frac{2000+V}{2000}

K_v = \frac{2000+2094.40}{2000}

= 2.0472

However, there is need to get the value of the tangential load(W^t), in order to achieve that, we have the following expression

W^t=\frac{T}{\frac{d}{2} }

W^t = \frac{63025*H}{\frac{n_pd}{2}}

W^t = \frac{63025*30}{2000*\frac{4}{2}}

W^t = 472.69 lbf

Finally, the bending stress is calculated via the formula:

\sigma = \frac{K_vW^tp}{FY}

\sigma = \frac{2.0472*472.69*5}{1*0.321}

\sigma = 15073.07 psi

\sigma = 15.07 ksi

∴ The estimate of the bending stress = 15.07 ksi

4 0
3 years ago
Read 2 more answers
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