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Answer:
Explanation:
Given,
initial angular speed, ω = 3,700 rev/min
=
final angular speed = 0 rad/s
Number of time it rotates= 46 times
angular displacement, θ = 2π x 46 = 92 π
Angular acceleration



Answer:
The minimum frequency required to ionize the photon is 111.31 ×
Hertz
Given:
Energy = 378 
To find:
Minimum frequency of light required to ionize magnesium = ?
Formula used:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
Solution:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
738 ×
= 6.63 ×
× v
v = 111.31 ×
Hertz
The minimum frequency required to ionize the photon is 111.31 ×
Hertz