Answer:
B) What is the enthalpy change, ∆H, for this reaction? Show your work to receive full credit (5 points) The enthalpy change is 150. To find it we must subtract energy of products (200) & the energy of reactants (50) so 200 – 50 equals 150.
Explanation:
B) What is the enthalpy change, ∆H, for this reaction? Show your work to receive full credit (5 points) The enthalpy change is 150. To find it we must subtract energy of products (200) & the energy of reactants (50) so 200 – 50 equals 150.
Opposite force in the opposite.
Answer:
from the position of the center of the Sun
Explanation:
As we know that mass of Sun and Jupiter is given as
![M_s = 1.98 \times 10^{30} kg](https://tex.z-dn.net/?f=M_s%20%3D%201.98%20%5Ctimes%2010%5E%7B30%7D%20kg)
![M_j = 1.89 \times 10^{27} kg](https://tex.z-dn.net/?f=M_j%20%3D%201.89%20%5Ctimes%2010%5E%7B27%7D%20kg)
distance between Sun and Jupiter is given as
![r = 7.78 \times 10^{11} m](https://tex.z-dn.net/?f=r%20%3D%207.78%20%5Ctimes%2010%5E%7B11%7D%20m)
now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them
so we will have
![r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}](https://tex.z-dn.net/?f=r_%7Bcm%7D%20%3D%20%5Cfrac%7BM_s%20r_1%20%2B%20M_j%20r_2%7D%7BM_s%20%2B%20M_j%7D)
![r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}](https://tex.z-dn.net/?f=r_%7Bcm%7D%20%3D%20%5Cfrac%7B1.98%20%5Ctimes%2010%5E%7B30%7D%20%280%29%20%2B%20%281.89%20%5Ctimes%2010%5E%7B27%7D%29%287.78%20%5Ctimes%2010%5E%7B11%7D%29%7D%7B1.98%20%5Ctimes%2010%5E%7B30%7D%20%2B%201.89%20%5Ctimes%2010%5E%7B27%7D%7D)
from the position of the center of the Sun
I think it is C. I hope I helped.
Answer:
<em>Explanation below</em>
Explanation:
<u>Speed vs Velocity
</u>
These are two similar physical concepts. They only differ in the fact that the velocity is vectorial, i.e. having magnitude and direction, and the speed is scalar, just the magnitude regardless of the direction. They are strongly related to the concepts of displacement and distance, which are the vectorial and scalar versions of the space traveled by a moving object. The velocity can be computed as
![\displaystyle \vec v=\frac{\vec r}{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cvec%20v%3D%5Cfrac%7B%5Cvec%20r%7D%7Bt%7D)
Where
is the position vector and t is the time. The speed is
![\displaystyle v=\frac{d}{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7Bd%7D%7Bt%7D)
To compute
, we only need to know the initial and final positions and subtract them. To compute d, we need to add all the distances traveled by the object, regardless of their directions.
Maggie walks to a friend's house, located 1500 meters from her place. The initial position is 0 and the final position is 1500 m. The displacement is
![\vec r=1500\ m \text{ to the south}](https://tex.z-dn.net/?f=%5Cvec%20r%3D1500%5C%20m%20%5Ctext%7B%20to%20the%20south%7D)
and the velocity is
![\displaystyle \vec v=\frac{1500}{45}=33.33\ m/s\text{ to the south}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cvec%20v%3D%5Cfrac%7B1500%7D%7B45%7D%3D33.33%5C%20m%2Fs%5Ctext%7B%20to%20the%20south%7D)
Now, we know Maggie had to make three different turns of direction to finally get there. This means her distance is more than 1500 m. Let's say she walked 500 m in all the turns, then the distance is
![d=1500+500=2000\ m](https://tex.z-dn.net/?f=d%3D1500%2B500%3D2000%5C%20m)
If she took the same time to reach her destiny, she would have to run faster, because her average speed is
![\displaystyle v=\frac{2000}{45}=44.44\ m/s](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7B2000%7D%7B45%7D%3D44.44%5C%20m%2Fs)