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dezoksy [38]
3 years ago
10

What are the answers is a quiz

Physics
1 answer:
defon3 years ago
4 0

Answer:19

Explanation:

You might be interested in
4.
Ulleksa [173]
The correct answer is C. Universal Gravitation (it was written by Issac Newton)
4 0
4 years ago
light waves are first transmitted through the ________ at the front of the eye and enter an opening called the ________ before s
viva [34]

The transmission of light waves is usually done through cornea of the eyes, then move through another opening which is regarded as pupil before it will get to the retina.

  • Light waves can be regarded as moving energy which contains microscopic particles known as photons.
  • The vision of the eye can be completed through the light wave passing through the components of the eyes and this process goes thus;
  • Light will move through the (cornea) which is situated at the front area of the eyes into lens.
  • Then both the cornea and the lens give room for the focusing of the light rays to the retina which is situated at the back of the eye .
  • Then through the help of the cells in the retina, the light will be absorbed and then be converted to  electrochemical impulses and then transfer it to the brain as well as optic nerve.

Therefore, light wave are form of tiny microscopic particles.

brainly.com/question/19734585?referrer=searchResults

8 0
3 years ago
If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take
viva [34]

Answer:

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

T = \sqrt{\frac{4\pi^2r^3 }{GM} }

where r = radius of orbit of Hubble Space Telescope

G = gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

M = Mass of earth

We are given that:

r = radius of the earth + distance of HST from earth

r = 6.38 * 10^6 + 598 = 6380598 m

M = 5.98 * 10^{24} kg

Therefore, T will be:

T = \sqrt{\frac{4*\pi^2 * 6380598^3 }{6.67408 * 10^{-11} * 5.98 * 10^{24}}}

T = 5069.04 secs

The orbital period of the Hubble Space Telescope is 5069.04 seconds.

7 0
3 years ago
Read 2 more answers
What can you conclude about the total mechanical energy of a pendulum as it swings back and forth?
Alchen [17]

Answer:

The total mechanical energy of a pendulum is conserved neglecting the friction.

Explanation:

  • When a simple pendulum swings back and forth, it has some energy associated with its motion.
  • The total energy of a simple pendulum in harmonic motion at any instant of time is equal to the sum of the potential and kinetic energy.
  • The potential energy of the simple pendulum is given by P.E = mgh
  • The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
  • When the pendulum swings to one end, its velocity equals zero temporarily where the potential energy becomes maximum.
  • When the pendulum reaches the vertical line, its velocity and kinetic energy become maximum.
  • Hence, the total mechanical energy of a pendulum as it swings back and forth is conserved neglecting the resistance.
8 0
4 years ago
A car and a heavy truck roll down a hill and reach the bottom at the same speed. Compared with the momentum of the truck, the mo
RoseWind [281]

Answer:

A. less

Explanation:

The momentum of an object is directly proportional to it mass and velocity. It is the product of mass and velocity of the object. Given as

Momentum (p) = Mass (m) \times Velocity (v)

So the momentum of car,

p_{c} = m_{c}\times v_{c}

Momentum of truck,

p_{t} = m_{t}\times v_{t}

We know that, mass of car is less than that of truck and velocity of the two are same. It is implied that, momentum of car will be less than that of truck.

3 0
4 years ago
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