Answer:
2.8248 g
Explanation:
First, consider the balanced chemical equation:

Then we calculate the number of moles in 4.11 g of citric acid:
n(citric acid)=
According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.
so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol
mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol
= 2.8248 g
Answer:
There are 10 moles of copper(II)sulfate.
Explanation:
We know that molarity is a concentration measure that expresses the moles of solute per liter of solution: in this case, being 1.30 molar, there are 1.30 moles of solute in 1 liter of solution. We solve with the following simple rule of three:
1 L solution-----2 moles of copper(II)sulfate
5 L solution----x= (5 L solution x 2 moles of copper(II)sulfate)/1 L solution
<em>x= 10 moles of copper(II)sulfate</em>