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schepotkina [342]
3 years ago
5

The frequency range for a normal human ear is between 20 Hz and 20 000 Hz. Using 330 m/s as the speed of sound, a. Calculate the

shortest wavelength of sound that can be heard: b. Calculate the longest wavelength of sound that can be heard:
Physics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

(a) 0.0165 m

(b) 16.5 m

Explanation:

Applying,

v = λf.................. Equation 1

Where v = velocity, f = frequency, λ = wave length.

make λ the subject of the equation

λ = v/f............. Equation 2

(a) Shortest wavelength (λ')

Given: f' = 20000 Hz, v = 330 m/s

Substitute these values into equation 2

λ' = 330/20000

λ' = 0.0165 m

(b) Longest wavelength (λ)

Given: v = 330 m/s, f = 20 Hz

Substitute these value into equation 2

λ = 330/20

λ = 16.5 m

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An electric pump rated at 1000W, takes 16 seconds to pump 100 kg of water out to a tank at a height of 10 m. what is the efficie
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Answer:

\boxed{\sf Efficiency \ of \ the \ motor = 62.5 \ \%}

Given:

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Explanation:

\boxed{ \bold{Output  \: power  \: (P_o)= \frac{mgh}{t}}}

\sf \implies P_o =  \frac{100 \times 10 \times 10}{16}

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\sf \implies P_o =  \frac{ \cancel{16} \times 625}{ \cancel{16}}

\sf \implies P_o = 625 \: W

\boxed{ \bold{Efficiency = \frac{Output \ Power \ (P_o)}{Input \ Power \ (P_i) } \times 100}}

\sf  \implies Efficiency  =  \frac{625}{10 \cancel{00}}  \times  \cancel{100}

\sf  \implies Efficiency  =  \frac{625}{10}

\sf  \implies Efficiency  = 62.5  \: \%

\therefore

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What is the product of mass and velocity called?
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