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USPshnik [31]
3 years ago
7

An electric pump rated at 1000W, takes 16 seconds to pump 100 kg of water out to a tank at a height of 10 m. what is the efficie

ncy of the motor?​
Physics
1 answer:
TEA [102]3 years ago
5 0

Answer:

\boxed{\sf Efficiency \ of \ the \ motor = 62.5 \ \%}

Given:

Input Power (\sf P_i)= 1000 W

Mass (m) = 100 kg

Height (h) = 10 m

Time (t) = 16 s

To Find:

Efficiency of the motor

Explanation:

\boxed{ \bold{Output  \: power  \: (P_o)= \frac{mgh}{t}}}

\sf \implies P_o =  \frac{100 \times 10 \times 10}{16}

\sf \implies P_o =  \frac{10000}{16}

\sf \implies P_o =  \frac{ \cancel{16} \times 625}{ \cancel{16}}

\sf \implies P_o = 625 \: W

\boxed{ \bold{Efficiency = \frac{Output \ Power \ (P_o)}{Input \ Power \ (P_i) } \times 100}}

\sf  \implies Efficiency  =  \frac{625}{10 \cancel{00}}  \times  \cancel{100}

\sf  \implies Efficiency  =  \frac{625}{10}

\sf  \implies Efficiency  = 62.5  \: \%

\therefore

Efficiency of the motor = 62.5 %

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Answer:

The distance traveled!

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3 years ago
Two astronauts of mass 100 kg are 2 m apart in outer space. What is the
fredd [130]

The force of gravity between the astronauts is 1.67\cdot 10^{-7}N

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

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m_1, m_2 are the masses of the two objects

r is the separation between them

In this problem, we have two astronauts, whose masses are:

m_1 = 100 kg\\m_2 = 100 kg

While the separation between the astronauts is

r = 2 m

Substituting into the equation, we can find the gravitational force between the two astronauts:

F=\frac{(6.67\cdot 10^{-11})(100)(100)}{2^2}=1.67\cdot 10^{-7}N

Learn more about gravitational force:

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4 0
3 years ago
Read 2 more answers
Projectile's horizontal range on level ground is R=v20sin2θ/g. At what launch angle or angles will the projectile land at half o
seraphim [82]

Answer:

\theta = 15^o \: or\: 75^o

Explanation:

As we know that the formula of range is given as

R = \frac{v^2sin2\theta}{g}

now we know that

maximum value of the range of the projectile is given as

R_{max} = \frac{v^2}{g}

now we need to find such angles for which the range is half the maximum value

so we will have

\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}

sin(2\theta) = \frac{1}{2}

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3 years ago
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Answer:

?

Explanation:

3 0
2 years ago
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vesna_86 [32]

The correct answer of this question is :  A) Change alternating current into direct current.

EXPLANATION :

As per the question, we are given vacuum tube. Vacuum tube can be of various types. Normally it contains two electrodes called cathode and anode which are enclosed in an evacuated glass chamber . There are also other types of vacuum tubes which contain extra electrodes like control grid .

The vacuum tube can be used as a rectifier. It means that it can be used as an electronic device which will convert alternating current into direct current. It may be a half wave rectifier or a full wave rectifier. Actually the direct current obtained during the rectification of alternating current is pulsating in nature.

Hence, the correct answer is that a vacuum tube can be used to change alternating current into direct current.


4 0
3 years ago
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