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sashaice [31]
3 years ago
5

A scale contains a spring with a spring constant of 291 N/m. Placing a mass on the scale causes the spring to be compressed by 2

.89 cm. Calculate the elastic potential energy stored in the spring.
Physics
1 answer:
WINSTONCH [101]3 years ago
6 0
E = 1/2*k*x^2 = 0.5*291*0.0289^2 = 0.12 J
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The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit
vovikov84 [41]

Gravitational force is given by, F= G\frac{mM}{R^{2}}

Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.

Gravitational force of the star on planet 1, F_{1}= G\frac{m_{1}M}{R^{2}}

Gravitational force of the star on planet 2, F_{2}= G\frac{3m_{1}M}{(3R)^{2}}

Ratio, \frac{F_{1}}{F_{2}}= \frac{\frac{Gm_{1}M}{R^{2}}}{\frac{G3m_{1}M}{(3R)^{2}}}

\frac{F_{1}}{F_{2}}=  \frac{3}{1}

Therefore, the gravitational force of the star on the planet 1 is three times that on planet 2.

6 0
3 years ago
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A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object
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Answer:

Resultant force, R = 10 N

Explanation:

It is given that,

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Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

R=\sqrt{F_x^2+F_y^2+F_xF_y\ cos\theta}

Here \theta=90^{\circ}

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So, the resultant force on the object is 10 N. Hence, this is the required solution.

6 0
3 years ago
How does wood and plastic relate to forces
WARRIOR [948]

Answer:

There are six kinds of forces that act on objects when they come into contact with one another: Normal force, applied force, frictional force, tension force, spring force and resisting force. These forces make objects change their motion or movement , the act of going from one place to another.

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3 years ago
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Answer:

30

Explanation:

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lukranit [14]

Answer:

Explanation:

I can tell you what the answers for the middle column are, but if you don't know how to solve total energy problems, they won't make any sense to you at all.

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Third row, KE = 183750 J

Fourth row, KE = 205800 J

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