Answer: The enthalpy of reaction is, -206.18 kJ
Explanation:-
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The final reaction is
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
Now adding (2) and (3) and subtracting (1) , we get :
Therefore, the enthalpy of reaction is, -206.18 kJ
Convert 98.7 g Sb2S3 to mols.
Convert mols Sb2S3 to mols Sb4O6 using the coefficients in the balanced equation.
Convert mols Sb4O6 to grams Sb4O6. (This is the theoretical yield.)
Convert grams Sb4O6 to percent Sb4O6.
%Sb4O6 = [72.4/theoretical yield]*100
So basically your answer is 85.5%
What are the half equations from earlier? It says use those and I can’t do it without them?