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3 years ago

The sum of pH and pOH for any aqueous solution equals .

Chemistry

1 answer:

Vsevolod [243]3 years ago

6 0

Answer:

pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7. Thus the sum of pH and pOH is 14

Explanation:

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What is 3623÷72×2(59)1(4)<8335×(3)(2x)

sineoko [7]

Answer:193

Explanation:

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3 years ago

The volume and amount of gas are constant in a tire. The initial pressure and temperature are 1.82 atm and 293 K. At what temper

vladimir1956 [14]

Answer:

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

Explanation:

Step 1: Data given

The initial pressure = 1.82 atm

The initial temperature = 293 K

The pressure will be increased to 2.35 atm

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒with P1 = the initial pressure = 1.82 atm

⇒with T1 = the initial temperature = 293 K

⇒with P2 = the increased pressure = 2.35 atm

⇒with T2 = the new temperature = TO BE DETERMINED

1.82atm / 293 K = 2.35 atm / T2

T2 = 2.35 atm / (1.82 atm/293 K)

T2 = 2.35 / 0.0062116

T2 = 378 K

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

4 0

3 years ago

Magnesium reacts with sodium fluoride to produce sodiunfluoride and elemental sodium.

vlabodo [156]

Explanation:

Mg+NaF. NaF+Mg

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8 0

2 years ago

A solution containing a mixture of metal cations was treated with dilute hcl and a precipitate formed. the solution was filtered

likoan [24]

If you really keep an eye on the flow chart, the only ions you can consider as being "Definitely not present" are: Cr3+, Fe3+, and Zn2+. The rest of the ions should be considered under "Possibly present", as we cannot conclude if any of the ions are "Definitely present".

6 0

3 years ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

3 years ago