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Phoenix [80]
3 years ago
11

Help me with this equation please

Physics
1 answer:
Vesna [10]3 years ago
3 0

Answer: Net force=20N a=F/m=4

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A 250 g air-track glider is attached to a spring with springconstant 4.0 N/m. Th damping constant due to air resistance is0.015
vaieri [72.5K]

Answer:

33.33 seconds

Explanation:

N=\dfrac{1}{e}N_0

N_0 = Initial length pulled = 20 cm

b = Damping constant = 0.015 kg/s

k = Spring constant = 4 N/m

m = Mass of glider = 250 g

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.25}{4}}\\\Rightarrow T=1.57079632679\ s

Using exponential decay formula

N=N_0e^{\dfrac{-bt}{m}}

Final amplitude = Initial times decay

\dfrac{1}{e}0.2=0.2e^{\dfrac{-0.015t}{2\times 0.25}}\\\Rightarrow 0.2=0.2e^{\frac{-0.015t}{2\cdot \:0.25}+1}\\\Rightarrow e^{\frac{-0.015t}{2\cdot \:0.25}+1}=1\\\Rightarrow \ln \left(e^{\frac{-0.015t}{2\cdot \:0.25}+1}\right)=\ln \left(1\right)\\\Rightarrow \left(\frac{-0.015t}{2\cdot \:0.25}+1\right)\ln \left(e\right)=\ln \left(1\right)\\\Rightarrow \frac{-0.015t}{2\cdot \:0.25}+1=\ln \left(1\right)\\\Rightarrow -\frac{0.015t}{0.5}=-1\\\Rightarrow -0.000225t=-0.0075\\\Rightarrow t=33.33\ s

The time taken is 33.33 seconds

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4 years ago
An object weighs 100 newtons on earth.What is its weight on the moon?
Pachacha [2.7K]

Answer:

a) The gravitational acceleration at the surface of the Moon is g moon=1.67 m/s  

2

The ratio of weights (for a given mass ) is the ratio of g-values, so  

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=(100N)(1.67/9.8)=17N.

(b) For the force on that  object caused by Earth's gravity to equal 17 N, then the free fall acceleration at its location must be  

ag

​  =1.67m/s  

2

 . Thus , .

ag

= r  2

Gm

E

⇒  

a  

g

Gm  

=1.5×10  

7

m

So the object would need to be a distance of r/R  

E

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=2.4 "radii" from Earth's center.

4 0
3 years ago
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How much heat does a freezer need to remove from 1kg of water at 40°C to make ice at 0°C? (You will need to use the specific hea
Montano1993 [528]

Answer:

Explanation:

Q = m c Δt

heat withdrawn to lower temperature by 40° C

Q = 1 X 1000 X 40 = 40,000 calories.

Q = mL

heat withdrawn to freeze water at 0°C to ice

= 1 x 80000 = 80,000 calories

total heat to be withdrawn = 120,000 calories. = 120,000 x 4.2 = 504 ,000 Joules.

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3 years ago
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jasenka [17]

Answer:

hi

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Which describes the motion of the box based on the resulting free-body diagram?
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D. (static equilibrium)

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I just took the test and made a 100 with that answer.

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