The contraption below has the following
1 answer:
Answer:
117.72 N
Explanation:
The given parameters are;
The mass m₁ = 2.0 × 10³ kg
The mass m₂ = 4.4 × 10² kg
The mass of the man, m₃ = 6.0 × 10 kg
The condition of the interaction of the surfaces = Frictionless surfaces
The
The tension in the string = The downward force = The weight of (m₂ + m₃) = (m₂ + m₃) × g
Let <em>a</em> represent the acceleration of the connected masses due to the weight of m₂, and m₃, we have;
(m₁ + m₂ + m₃) × a = (m₂ + m₃) × g
∴ a = (m₂ + m₃) × g/(m₁ + m₂ + m₃)
Which gives;
a = (4.4 × 10²+ 6.0 × 10) × 9.81/(2.0 × 10³+ 4.4 × 10²+ 6.0 × 10) = 1.962
The downward acceleration, a = 1.962 m/s²
The apparent weight of the man = The mass of the man, m₃ × The acceleration, <em>a</em>
∴ The apparent weight of the man = 6.0×10 kg ×1.962 m/s² = 117.72 N
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Answer:
This means that the center of mass is locates 0.72m from the 750N force
Explanation:
Since the board is 2.2m long, that will be the length of the board.
Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.
Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x
Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.
Moment = force × perpendicular distance
For ACW moment;
Moment = 750×x = 750x
For the CW moment;
Moment = 360 × (2.2-x)
Moment = 792-360x
Equating ACW moment to the clockwise moment we have;
750x = 792-360x
750x+360x = 792
1110x = 792
x = 792/1110
x = 0.72m
This means that the center of mass is locates 0.72m from the 750N force
Complete question:
A pendulum of length L = 48.5 cm and mass m = 169 g is released from rest when the cord makes an angle of 65.4° with the vertical. What is the speed of the mass (m/s) upon reaching its lowest point?
Answer:
The speed of the mass upon reaching its lowest point is 2.36m/s
Explanation:
To obtain the speed of the mass upon reaching its lowest point, we apply the principle of conservation of mechanical energy. At the lowest point, the kinetic energy of the pendulum is maximum and at the highest point, the vertical displacement is maximum, thus potential energy is maximum.
Kinetic energy at the lowest point = Potential energy at the highest point
From my explanation above, h is the vertical displacement, when potential energy of the pendulum is maximum. Considering a right angled triangle, this vertical displacement, h is the adjacent of the triangle, and it is equal to
L - Lcosθ.
h = 48.5 - 48.5cos(65.4) = 28.31 cm = 0.2831 m
Therefore, the speed of the mass upon reaching its lowest point is 2.36m/s