The contraption below has the following
1 answer:
Answer:
117.72 N
Explanation:
The given parameters are;
The mass m₁ = 2.0 × 10³ kg
The mass m₂ = 4.4 × 10² kg
The mass of the man, m₃ = 6.0 × 10 kg
The condition of the interaction of the surfaces = Frictionless surfaces
The
The tension in the string = The downward force = The weight of (m₂ + m₃) = (m₂ + m₃) × g
Let <em>a</em> represent the acceleration of the connected masses due to the weight of m₂, and m₃, we have;
(m₁ + m₂ + m₃) × a = (m₂ + m₃) × g
∴ a = (m₂ + m₃) × g/(m₁ + m₂ + m₃)
Which gives;
a = (4.4 × 10²+ 6.0 × 10) × 9.81/(2.0 × 10³+ 4.4 × 10²+ 6.0 × 10) = 1.962
The downward acceleration, a = 1.962 m/s²
The apparent weight of the man = The mass of the man, m₃ × The acceleration, <em>a</em>
∴ The apparent weight of the man = 6.0×10 kg ×1.962 m/s² = 117.72 N
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