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ICE Princess25 [194]

3 years ago

5

How do I solve for the maximum speed and height given those accelerations? (please give the formula so I can solve these types o

f questions later on)

1 answer:

Sphinxa [80]3 years ago

5 0

It depends on how you want to solve it you can solve it in many different meathods:$

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in terms of the wavelength of the sound wave, about how far below the open end of the resonance tube is the first resonant posit

notka56 [123]

The first resonant position below the open end of the resonance tube is; <em><u>one-quarter of the wavelength</u></em>

In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.

However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.

This means that the standing wave will have one-quarter of the wavelength in the test tube.

Thus;

L = ¼λ

Read more at; brainly.com/question/17086525

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2 years ago

How do the sun energy flow through the earth system

storchak [24]

The sun's energy flow through the earth's system by it moving through the earth's atmosphere.

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3 years ago

3) Find the missing parts of the triangle (angle and/or sides).<br>

oee [108]

Answer:

44.4°

Explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

You're given an unknown angle, the adjacent side to that angle, and the hypotenuse. So use cosine.

Cosine = Adjacent / Hypotenuse

cos A = 10 / 14

A = cos⁻¹(5/7)

A ≈ 44.4°

8 0

3 years ago

In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r

Illusion [34]

Answer:

the weight of the rider is 493.53 N

Explanation:

Given the data in the question and as illustrated in the image below,

Tension T = 1900 N

the rider is moving at a constant speed so the net force in the horizontal direction will be 0

In the horizontal direction

F $_{sail$ cos( 30° ) = Tcos ( 17° )

F $_{sail$ = Tcos( 17° ) / cos( 30° )

F $_{sail$ = 1900cos( 17° ) / cos( 30° )

F $_{sail$ = 2098.07 N

Now, In the vertical direction,

F $_{sail$ sin( 30° ) = W + T sin( 17° )

W = F $_{sail$ sin( 30° ) - T sin( 17° )

W = 2098.07sin( 30° ) - 1900sin( 17° )

W = 1049.035 - 555.506

W = 493.53 N

Therefore, the weight of the rider is 493.53 N

7 0

3 years ago

Objects 1 and 2 attract each other with a gravitational force

Ivanshal [37]

Answer:

27unit

Explanation:

18×3/2= 9×3= 27unit

3 0

3 years ago

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