<h3>Explanation</h3>
,
where
is the current;
is the drift speed;
is the cross-section area of the wire, 
is the number of charge carrier per unit volume, and
is the charge on each charge carrier.
Area of a circular cross-section:
,
where
is the radius of the wire.
and are the same for all four samples, for they are made out of the same material.
As a result, of each wire is directly proportional to 
where the value of 
is constant.
For each of the four wires:
.
How do the four wires rank by their current?
d > a > b > c.
Hey there,
Answer:
A, True
Hope this helps :D
<em>~Top☺
</em>
Explanation:
Orbital period = 2 x 10⁶s
Total radius = 2.5 x 10¹²m
Unknown:
Tangential speed of the satellite = ?
Solution:
The tangential speed simply expresses the rate at which the distance moves around its orbit with time.
Since the orbit is taken to be circular;
Tangential speed = 
r is the radius
t is the time or orbital radius
Tangential speed = ![\frac{2 x 3.14 x 2.5 x 10¹²}{2 x10[tex]^{6}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20x%203.14%20x%202.5%20x%2010%C2%B9%C2%B2%7D%7B2%20x10%5Btex%5D%5E%7B6%7D)
}[/tex]
Tangential speed = 7.85 x 10⁶m/s
Learn more:
Circular motion brainly.com/question/2562955
#learnwithBrainly
Answer:
a) 14.2sec
b) 1394m away if horizontal speed never changes
c) 9.8m/s
Explanation:
Answer: 156.02 metre.
Explanation:
Give that a certain car traveling 33.0mph skids to a stop in 39m from the point where the brakes were applied.
Let us use third equation of motion,
V^2 = U^2 + 2as
Since the car is decelerating, V = 0
And acceleration a will be negative.
U = 33 mph
S = 39 m
Substitute both into the formula
0 = 33^2 - 2 × a × 39
0 = 1089 - 78a
78a = 1089
a = 1089 / 78
a = 13.96 m/h^2
If we assume that the car decelerate at the same rate.
the distance the car will stop had it been going 66.0mph will be achieved by using the same formula
V^2 = U^2 + 2as
0 = 66^2 - 2 × 13.96 × S
4356 = 27.92S
S = 4356 / 27.92
S = 156.02 m
Therefore, the car would stop at
156.02 m
