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3 years ago

Please i need help with this question.

Chemistry

1 answer:

tatiyna3 years ago

3 0

Answer:

Explanation:

Please see the attached picture for the explanation.

Le Châtelier's principle:

When a stress is applied to a system at equilibrium, the system will respond by shifting in the direction that opposes/ minimizes the effect of the stress.

• This stress could be the addition or removal of a product or reactant, changes in the concentration of the products or reactants, or a change in temperature.

☆ Why can heat be written on the same side of the products when the reaction is exothermic?

• Exothermic means that heat is released, thus heat can be treated as a product.

• I like to remember it as Exothermic → Exit

You might be interested in

What changes occur in O + O = O2

ozzi

Answer:

They went from atoms to oxygen molecule.

Explanation:

I'm not sure if this is the answer your teacher is looking for, but in simple terms you had 2 oxygen atoms. Together they make an oxygen molecule, which is the stuff we breathe.

5 0

3 years ago

Two moles of an ideal gas are placed in a container whose volume is 2.3 x 10^-3 m3. The absolute pressure of the gas is 6.9 x 10

PtichkaEL [24]

Answer:

$K.E.=1.97\times 10^{-21}\ J$

Explanation:

Given that:-

Pressure = $6.9\times 10^5\ Pa$

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

Given the value of pressure = 43,836 Pa

So,

$6.9\times 10^5\ Pa$ = $\frac{6.9\times 10^5}{101325}$ atm

Pressure = 6.80977 atm

Volume = $2.3\times 10^{-3}\ m^3$ = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

$K.E.=\frac{3}{2}\times K\times T$

k is Boltzmann's constant = $1.38\times 10^{-23}\ J/K$

T is the temperature

So, $K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J$

$K.E.=1.97\times 10^{-21}\ J$

3 0

3 years ago

For a particular isomer of C8H18, the combustion reaction produces 5104.1 kJ of heat per mole of C8H18(g) consumed, under standa

Vladimir79 [104]

Answer:

Explanation:

Hello,

Considering the chemical reaction, the enthalpy of reaction is given by:

ΔH°rxn=ΔfHCO2+ΔfHH2O-ΔfHC8H18

(ΔfHO2=0)

Taking into account that the reaction produces energy, ΔH°rxn is negative. No, solving for ΔfHC8H18:

ΔfHC8H18=-ΔH°rxn+8*ΔfHCO2+9*ΔfHH2O

ΔfHC8H18=-(-5104.1 kJ/mol)+9*(-292.74kJ/mol)+8*(-393.5 kJ/mol)

ΔfHC8H18=-678.56 kJ/mol

Best regards.

3 0

3 years ago

What is the molar mass of a gas if 0.281 g of the gas occupies a volume of 125 ml at a temperature 126 °c and a pressure of 777

AleksAgata [21]

Answer : 72.05 g/mol

Explanation : 

Let's assume that the given gas is an ideal gas. Then we can use ideal gas equation,
PV = nRT

Where,
P = Pressure of the gas (Pa)
V = volume of the gas (m³)
n = number of moles (mol)
R = Universal gas constant (8.314 J mol⁻¹ K⁻¹)
T = temperature in Kelvin (K)

The given data for the gas is,
P = 777 torr = 103591 Pa
V = 125 mL = 125 x 10⁻⁶ m³
T = (126 + 273) = 399 K
R = 8.314 J mol⁻¹ K⁻¹
n = ?

By applying the formula,
103591 Pa x 125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 399 K
n = 3.90 x 10⁻³ mol

Moles (mol) = mass (g) / molar mass (g/mol)

Mass of the gas = 0.281 g
Moles of the gas = 3.90 x 10⁻³ mol
Hence,
molar mass of the gas = mass / moles
= 0.281 g / 3.90 x 10⁻³ mol
 = 72.05 g/mol

7 0

4 years ago

Read 2 more answers

A piece of mental with a mass of 106 g is placed in a 50 mL graduated cylinder.The volume rises from 20 mL to 31 mL. What is the

garik1379 [7]

Answer:

9.64g/mL

Explanation:

Given parameters:

Mass of the metal = 106g

Volume of cylinder = 50mL

Volume difference = 31mL - 20mL = 11mL

Unknown:

Density of the metal = ?

Solution:

To find the density of the metal, we use;

Density = $\frac{mass}{volume}$

Density = $\frac{106}{11}$ = 9.64g/mL

8 0

3 years ago