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prohojiy [21]
2 years ago
11

In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up which of the following? Select all that apply. A

. a population B. part of a community C. part of an ecosystem​
Chemistry
1 answer:
Gre4nikov [31]2 years ago
7 0

The pincushion moss, the echeveria, and the moon cactus in a terrarium make up a community.

<h3>What is a community of organisms?</h3>

A community of organisms refers to a group of organisms of different species which are found living together in the same habitat.

Populations of organisms of different species within the same habitat constitute a community.

The pincushion moss, the echeveria, and the moon cactus are all different species found within the same habitat, a terrarium.

Therefore, the different species of organisms in the terrarium make up a community.

Learn more about community of organisms at: brainly.com/question/18715575

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Lithium has the electron arrangement 2,1. When lithium forms an ion,
iragen [17]

Answer:

when lithium forms an ion it donates 1 electron

which makes its electron configuration to become 2

4 0
3 years ago
Describe Bohr’s model of the atom consisted of a central
MariettaO [177]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The Bohr model depicts an atom as a small, positively charged nucleus surrounded by electrons.These electrons travel in circular orbit around the nucleus similar in structure to the solar system,except electrostatic forces rather than gravity provide attraction.Electron orbit around the nucleus resembles that of planets around the sun in the solar system.

        The Bohr model was an improvement  on the earlier cubic model(1902),the plum pudding model(1904) the saturnine model (1904) the rutherford model (1911) since the Bohr model is a quantum physics based modification of the Rutherford may source combine the two:the Rutherford-Bohr model

Although revolutionary at the time,the Bohr model is a relatively primitive model of the hydrogen atom compared to the  valence shell atom.As an initial hypothesis it was derived as a first order approximation to describe the hydrogen atom.Due to its simplicity and correct results for selected systems.

In 913 Bohr suggested that electrons could only have certain classical motions:

  1. Electrons in atoms orbit the nucleus.
  2. The electrons can only orbit stably,without radiating in certain orbits at a certain discrete set of distances from the nucleus.These orbit are associated with definite energies and are also called energy shells or energy levels.
  3. Electrons can only gives or lose energy by jumping from one allowed orbit to another,absorbing or emitting electromagnetic radiation with a frequency (v) determined by the energy difference of the levels according to the plank relation.
4 0
2 years ago
What is easier to observe about an object,it’s physical properties or it’s chemical properties. Explain why.
Sladkaya [172]

Answer:

Physical Properties

Explanation:

You are able to see physical properties but are unable to see chemical properties.

7 0
3 years ago
How many liters of o2 do you have if you have 5.8 moles of o2
polet [3.4K]

Answer:

130 Liters

Explanation:

if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)

3 0
3 years ago
Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe
jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

n=\frac{m}{M_m}

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol

Now we can find the pressure of the gas by using the ideal gas law:

pV=nRT

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm

8 0
3 years ago
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