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prohojiy [21]
2 years ago
11

In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up which of the following? Select all that apply. A

. a population B. part of a community C. part of an ecosystem​
Chemistry
1 answer:
Gre4nikov [31]2 years ago
7 0

The pincushion moss, the echeveria, and the moon cactus in a terrarium make up a community.

<h3>What is a community of organisms?</h3>

A community of organisms refers to a group of organisms of different species which are found living together in the same habitat.

Populations of organisms of different species within the same habitat constitute a community.

The pincushion moss, the echeveria, and the moon cactus are all different species found within the same habitat, a terrarium.

Therefore, the different species of organisms in the terrarium make up a community.

Learn more about community of organisms at: brainly.com/question/18715575

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If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?
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Which answer below correctly the type of change and explanation for the separation of the iron with sulfur?
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What is the % composition of Carbon in Chromium (iii) Carbonate
photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

\begin{gathered} C\rightarrow3\times12=36 \\  \\ O\rightarrow9\times16=144 \\  \\ Cr\rightarrow2\times52=104 \end{gathered}

The molar mass will be thus:

M=36+104+144=284\text{ g/mol}

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\  \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}

The percent composition of Carbon is thus 12.7 %.

8 0
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3 0
3 years ago
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Then to find the mass, multiply the volume with the density. The calculation would be: 5.74x10^6L x 0.179g/L= 1.027 x 10^6 g= 1027kg
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