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Andreas93 [3]
3 years ago
8

Write empirical formula

Chemistry
1 answer:
andrew11 [14]3 years ago
3 0

Answer:

Pb(ClO_{3})_{4}\\Pb(MnO_{4})_{4}\\Fe(ClO_{3})_{3}\\\Fe(MnO_{4})_{3}\\

Explanation:

Pb^{4+}(ClO_{3}^{-})_{4}--->Pb(ClO_{3})_{4}\\Pb^{4+}(MnO_{4}^{-})_{4}--->Pb(MnO_{4})_{4}\\Fe^{3+}(ClO_{3}^{-})_{3}--->Fe(ClO_{3})_{3}\\\Fe^{3+}(MnO_{4}^{-})_{3}--->Fe(MnO_{4})_{3}\\

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what is the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22c to 66c
aniked [119]

Answer :

the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

Explanation:

The answer can be calculated using the formula

Q = mCрΔT

where

Q is the amount of heat required in joules to raise the temperature.

m is the mass of the sample in Kg.

Cp is the specific heat of the sample in J/Kg°C.

ΔT is the change in temperature required.

Here, m = 49.5-gram = 0.0495 kg

Cp = 4.18 J/Kg°C (for water)

T₁ = 22°C  ; T₂ = 66°C

ΔT =  66 - 22 = 44

Substituting values in Q = mCрΔT

Q = (0.0495)(4.18)(44)

                  Q = 9.104 J

5 0
3 years ago
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Lubov Fominskaja [6]

Explanation:

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7 0
3 years ago
Mercuric oxide (HgO) is heated and forms liquid mercury (Hg) and oxygen (O2) gas. How would you characterize this reaction?
My name is Ann [436]

Answer:

Decomposition reaction.

Explanation:

Decomposition reaction -

It is the type of reaction, where a single entity breaks down into various products under the influence of some external factors , like heat and sunlight , is referred to as a decomposition reaction.

From the question,

The reaction is -

2 HgO  →  2 Hg + O₂

Hence ,

A single compound HgO breaks down to two entities , i.e. , Hg and  O₂.

             

7 0
4 years ago
The molar mass of argon is 40 g/mol. what is the molar mass of a gas if it effuses at 0.91 times the speed of argon gas?
Gemiola [76]
To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas      2 = unknown gas
r2 = 0.91r1r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40M2 = 48.30 g/mol
8 0
4 years ago
Read 2 more answers
Why could element 119 be right below Fr in the periodic table if discovered?
faust18 [17]

Answer:

Ununennium, also known as eka-francium or element 119, is the hypothetical chemical element with symbol Uue and atomic number 119. Ununennium and Uue are the temporary systematic IUPAC name and symbol respectively, which are used until the element is discovered, confirmed, and a permanent name is decided upon. In the periodic table of the elements, it is expected to be an s-block element, an alkali metal, and the first element in the eighth period. It is the lightest element that has not yet been synthesized.

Explanation:

7 0
3 years ago
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