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Andreas93 [3]
3 years ago
8

Write empirical formula

Chemistry
1 answer:
andrew11 [14]3 years ago
3 0

Answer:

Pb(ClO_{3})_{4}\\Pb(MnO_{4})_{4}\\Fe(ClO_{3})_{3}\\\Fe(MnO_{4})_{3}\\

Explanation:

Pb^{4+}(ClO_{3}^{-})_{4}--->Pb(ClO_{3})_{4}\\Pb^{4+}(MnO_{4}^{-})_{4}--->Pb(MnO_{4})_{4}\\Fe^{3+}(ClO_{3}^{-})_{3}--->Fe(ClO_{3})_{3}\\\Fe^{3+}(MnO_{4}^{-})_{3}--->Fe(MnO_{4})_{3}\\

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patriot [66]

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

  • A good buffer system contains a weak acid and its salt or a weak base and its salt.
  • In this case; A solution that is 0.10 M HCN and 0.10 M LiCN, would make a good buffer system.
  • HCN is a weak acid, while LiCN is a salt of the weak acid, that is, CN- conjugate of the acid.
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3 years ago
Even though so much energy is required to form a metal cation with a 2+ charge, the alkaline earth metals form halides with gene
nasty-shy [4]

The ∆Hrxn of the reaction is -394.5kJ/mol.

<h3>What is alkaline earth metal? </h3>

The alkaline earth metals are those elements which correspond to group 2 of the modern periodic table.

All elements of this group forms a cation of +2 charge.

The other elements of this group are:

Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium.

<h3>What is Halogen? </h3>

The Halogen elements are present in group 17 of the modern periodic table.

All elements of this groups forms anions of -1 charge.

The elements of this group are:

Fluorine, Chlorine, bromine, iodine, and astatine.

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We have following data of bond energy in kJ/mol:

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Mg—Cl = 783.5

Since, one mole of Mg react with one mole of Cl atom to form one mole of MgCl

∆Hrxn = 738-349-783.5

∆Hrxn = -394.5kJ/mol.

Thus, we concluded that the ∆Hrxn of the reaction is -394.5kJ/mol.

learn more about bond energy:

brainly.com/question/13526463

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2 years ago
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