For a and b, you need to divide it by Avogadro’s number to find the answer.
a. (6.022x10^23)/6.022x10^23 = 1 mole of Ne
b. (3.011x10^23)/6.022x10^23 = 0.5 moles of Mg
For c and d, you’ll use the mass provided divided by the molar mass to find the number of moles.
Pb molar mass = 207.2 g/mol
c. (3.25x10^5)/207.2 = 1.57x10^3 moles of Pb
For d, I can’t tell if is Cu, C or something else but you can follow the steps above to solve the problem.
To get density, you divide mass by volume. You get 3.2954.
This process is called meiosis! good luck!
Since the heat of combustion of butane is higher than that of propane, butane will produce more heat per gram when burned compared to propane.
The heat of combustion of a compound refers to the heat evolved when one mole of the compound is burnt under standard conditions. This heat of combustion increases from methane upwards.
Since the heat of combustion of alkanes increases according to increasing molar mass, butane will produce more heat per gram when burned compared to propane.
Learn more about heat of combustion: brainly.com/question/25312146