Find the number in the boxes, geometry homework !

Valentin [98]

Part A)

The given equation is:

$25 x^{2} +10x+1=0$

The radicand or discriminant(d) of the equation will be:

$d=(10)^{2}-4(25)(1) \\ \\ 
d=100-100 \\ \\ 
d=0$

Since the discriminant is equal to 0, the given quadratic equation has only 1 root. In other words we can say the the given equation is a perfect square.

Part B)

The given equation is:

$4 x^{2} -4x+1=0$

We can solve this expression by factorization. Factors of middle term are to be made in such a way that their product equals the product of first and third term and sum is equal to the middle term i.e. product should be 4x² and sum should be -4x.
So the two such terms are -2x and -2x. Using the factors and simplifying the equation by taking common we get:

$4 x^{2} -2x-2x+1=0 \\ \\ 
2x(2x-1)-1(2x-1)=0 \\ \\ 
(2x-1)(2x-1)=0 \\ \\ 
(2x-1) ^{2}=0 \\ \\ 
2x-1=0 \\ \\ 
x= \frac{1}{2}$

4 0

3 years ago

If a cat with short brown hair (llBb) is crossed with a cat with long black hair (Llbb), what is the likelihood that there will

Advocard [28]

Bb = brown hair phenotype

bb = black hair phenotype

we see that B = brown hair is the dominant gene while b = black hair is the recessive gene

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ll = short hair, this is a lowercase L

Ll = long hair

In this case, l = short hair is the recessive gene while L = long hair is the dominant gene.

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Check out the diagram below to see the dihybrid crosses for each of the hair color and hair length genotypes. From there, I show all of the genotypes possible for any offspring. Those genotypes are

LlBb = long brown hair (comes up 4 times)
Llbb = long black hair (comes up 4 times)
llBb = short brown hair (comes up 4 times)
llbb = short black hair (comes up 4 times)

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If we are talking about 1 offspring, then it is not possible for him/her to have both "long black hair AND short brown hair" as the instructions state. So let's consider two offspring instead.

The probability of having long black hair is 4/16 = 1/4 as there are 4 cases of Llbb out of 16 cases total. Similarly, the probability of getting llBb is 4/16 = 1/4 as well, for pretty much the same reasons.

The probability of having both events occur is (1/4)*(1/4) = 1/16

The multiplication of probabilities is valid because the two events are independent.

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<h3>Final Answer: A) 1/16</h3>

5 0

3 years ago

Find the reciprocal of each number. Do not simplify. 5/4

posledela

Google it.... <em> </em>I just did and there is a video.

7 0

3 years ago

Someone please tell me and maybe ill pay you

rjkz [21]

4x = 6x -10
2x = 10
x = 5

answer
x = 5

6 0

4 years ago

What types of problems can be solved using the greatest common factor what type of problems can be solved using the least common

Tanzania [10]

There could be problems like there is a light which would flicker in every 7 seconds and there is another one which would flicker in every 8 seconds. So, how many times would they flicker until they would flicker at the same time?

6 0

4 years ago