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3 years ago

What is the pH of a solution with [H+]=7.0 * 10^-2

Chemistry

1 answer:

erastova [34]3 years ago

6 0

Answer:

1.15

Explanation: I hope my calculations are correct

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Why did Thomson’s results from experimenting with cathode rays cause a big change in scientific thought about atoms?

IceJOKER [234]

Answer:

D, because he discovered electrons

Explanation:

8 0

3 years ago

Read 2 more answers

Atoms of iron (fe) and sulfur (s) form iron sulfide (fes) when the iron atom donates electrons to the sulfur atom. the type of b

marysya [2.9K]

Answer:

The type of bond formed in FeS would be <u>Polar Covalent Bond</u>.

Explanation:

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent Bond

Between 0.4 and 1.7 then it is Polar Covalent Bond

Greater than 1.7 then it is Ionic Bond

For Fe and S,

E.N of Sulfur = 2.58

E.N of Iron = 1.83

________

E.N Difference 0.75 (Polar Covalent Bond)

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3 years ago

What is carboxylic acid?

maksim [4K]

Answer:

Carboxylic acid

A carboxylic acid is an organic acid that contains a carboxyl group attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO₂H, with R referring to the alkyl, alkenyl, aryl, or other group. Carboxylic acids occur widely. Important examples include the amino acids and fatty acids.

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2 years ago

Convert 25.4 grams of barium phosphate, Ba3(PO4)2 to formula units.

Salsk061 [2.6K]

To solve this questions you first need to find the number of moles of barium phosphate you have. The molar mass of barium phosphate is 601.93g/mol.
24.4/601.83 = 0.0402 moles barium phosphate
Then you need to use avagadro’s number, 6.022 x 10^23, which is the number of molecules or formula units in a mole.

6.022 x 10^23 * 0.0402 = 2.42 x 10^22 formula units

7 0

2 years ago

Draw the most stable resonance structure for the intermediate in the electrophilic aromatic bromination of aniline, anisole, and

ASHA 777 [7]

Answer:

Here's what I get

Explanation:

(a) Intermediates

The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).

(b) Relative Stabilities

The relative stabilities decrease in the order shown.

N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.

(c) Relative reactivities

The relative reactivities would be

C₆H₅-NH₂ > C₆H₅-OCH₃ > C₆H₅-NHCOCH₃

4 0

3 years ago