Answer:
It will not dissolve. More crystals will separate from the solution.
Step-by-step explanation:
If you add a crystal of ammonium nitrate to a supersaturated solution of the solute, it will not dissolve.
Instead, it will act as a "seed" on which more ammonium nitrate crystals will form.
They will separate from the solution as long, colourless, needle-like crystals until the solution is no longer supersaturated.
Answer:
r² x h
Explanation:
A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.
The volume of cylinder is given as:
Volume of a cylinder = Area x height
Volume of a cylinder = r² x h
Therefore density of the can;
Density =
Answer:
sp³d¹ hybridization
Explanation:
Given Cl as central element with three F substrates ...
The VSEPR structure indicates 5 hybrid orbitals that contain 2 diamagnetic orbitals (non-bonded e⁻-pairs) and 3 paramagnetic orbitals (single, non-paired electron for covalent bonding with fluorine) giving a trigonal bypyrimidal parent with a T-shaped geometry.
Valence bond theory predicts the following during bonding:
Cl:[Ne]3s²3p²p²p¹3d⁰
=> [Ne]3s²p²p¹p¹d¹
=> [Ne]3(sp³d)²(sp³d)²(sp³d)¹(sp³d)¹(sp³d)¹
giving 3 ( [Cl](sp³d) - [F]2p¹ ) sigma bonds and 2 non-bonded pairs on Cl.
Note the following images:
Non-bonded electron pairs are in plane of parent geometry and Fluorides covalently bonded to central element Chloride forming the T-shaped geometry.
