Phosphorus can be prepared from calcium phosphate by the following reaction:
Phosphorite is a mineral that contains 
plus other non-phosphorus-containing compounds. What is the maximum amount of 
that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% by mass? Assume an excess of the other reactants.
Answer: Thus the maximum amount of that can be produced is 0.345 kg
Explanation:
Given mass of phosphorite = 2.3 kg
As given percentage of phosphorite is = 
According to stoichiometry:
2 moles of phosphorite gives = 1 mole of
Thus 5.56 moles of phosphorite give= 
of
Mass of 
Thus the maximum amount of that can be produced is 0.345 kg
Answer:
<h3>The answer is 526.32 mL</h3>
Explanation:
To find the original volume we use the formula for Boyle's law which is
Since we are finding the original volume
From the question we have
We have the final answer as
<h3>526.32 mL</h3>
Hope this helps you
Avogadro's law states that in one mole of a substance, there are 
molecules.
This means that in 1.55 moles, there are 
Hello!
The net chemical equation between Sodium Bicarbonate and H₂SO₄ is the following one:
2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2H₂O + 2CO₂
To calculate the amount of Sodium Bicarbonate needed to neutralize 1000 L of 0,350 M H₂SO₄ we'll need to use the following conversion factor, to go from the volume of H₂SO₄ to grams of Sodium Bicarbonate:
So, to neutralize 1000 L of 0,350 moles of H₂SO₄ you'll need
58804,9 grams of NaHCO₃
Yea this makes me happy I love talking about bonds Here is a explanation since there is no question.
In the ionic bond that creates sodium fluoride, for example, the element sodium loses one of its 11 electrons to balance the 9 electrons in Fluoride because the ionization energy of sodium (the charge required to lose an electron) is low.
Glad to help
Have a wonderful day
