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icang [17]
2 years ago
5

A sphere of metal has a mass of 1431 g and a diameter of 5.80 cm. What is the density of metal in g/cm3

Physics
1 answer:
Dmitriy789 [7]2 years ago
4 0

Answer:

see below

Explanation:

You will need t find the volume of the sphere

 4/3 pi r^3    divide into the mass

1431 / (4/3 pi (5.8)^3) = 14 gm /cm^3

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A block is on a frictionless table, on earth. The block accelerates at 7.5 m/s when a 70 N horizontal force is applied to it. Th
Liono4ka [1.6K]

Answer:

The weight of the block on the moon is 15 kg.

Explanation:

It is given that,

The acceleration of the block, a = 7.5 m/s²

Force applied to the box, F = 70 N

The mass of the block will be, m=\dfrac{F}{a}

m=\dfrac{70\ N}{7.5\ m/s^2}

m = 9.34 kg

The block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s². The mass of the object remains the same. It weight W is given by :

W=m\times g

W=9.34\ kg\times 1.62\ m/s^2

W = 15.13 N

or

W = 15 N

So, the weight of the block on the moon is 15 kg. Hence, this is the required solution.

3 0
3 years ago
On the surface of Earth, the force of gravity acting on one kilogram is: *
Murrr4er [49]

Your answer would be:

Option (B) : 2.2 Pounds

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4 0
3 years ago
A physics student uses a spring loaded launcher to fire a 58 gram projectile horizontally. The projectile leaves the launcher at
timofeeve [1]

Answer:

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Explanation:

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3 0
3 years ago
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Dmitry [639]

equal and opposite reaction.

5 0
3 years ago
A parallel-plate capacitor is connected to a battery. After it becomes charged, the capacitor is disconnected from the battery a
Inessa [10]

Answer:

The potential difference between the plates increases

Explanation:

As we know that the capacitance of the capacitor is given by:

q = CV         (1)

where

q = charge

C = capacitance

V = Voltage or Potential Difference

Also, the capacitance of a parallel plate capacitor is given as:

C = \frac{\epsilon_{o}A}{D}           (2)

where

\epsilon_{o} = permittivity of free space or vacuum

A = Area of the plates

D = Separation distance between the plates

Now, from eqn (1) and (2):

V = \frac{qD}{A\epsilon_{o}}

Now, from the above eqn  we can say that:

Potential difference depends directly on the separation distance between the plates of the capacitor and is inversely dependent on the area of the plates of the capacitor.

Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.

4 0
3 years ago
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