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NNADVOKAT [17]
3 years ago
9

Which of Earth’s spheres is composed of a mixture of gases?

Physics
2 answers:
mixer [17]3 years ago
6 0

Answer:

the earth's atmosphere

Explanation:

hope that helps

vlabodo [156]3 years ago
5 0

Answer:

Earth's atmosphere is a layer of gases surrounding the planet Earth and retained by the Earth's gravity. It contains roughly 78% nitrogen and 21% oxygen 0.97% argon and carbon dioxide 0.04% trace amounts of other gases, and water vapor. This mixture of gases is commonly known as air.  Explanation:

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State one advantage and disadvantage of friction
yuradex [85]

Answer:

  1. Advantage: Helps us to walk without slipping.
  2. Helps machines work

Disadvantage:

  1. We slip on a wet floor.
  2. Causes the smoothness of tires and smoothness of shoes soul.

5 0
2 years ago
Which of these are part of the electromagnetic spectrum?
bazaltina [42]

Answer: A, C, E

Explanation:

Gamma rays, Microwaves, and Radio waves

6 0
2 years ago
Read 2 more answers
A particle is released as part of an experiment. Its speed t seconds after release is given by v (t )equalsnegative 0.4 t square
torisob [31]

Answer:

a) 2.933 m

b) 4.534 m

Explanation:

We're given the equation

v(t) = -0.4t² + 2t

If we're to find the distance, then we'd have to integrate the velocity, since integration of velocity gives distance, just as differentiation of distance gives velocity.

See attachment for the calculations

The conclusion of the attachment will be

7.467 - 2.933 and that is 4.534 m

Thus, The distance it travels in the second 2 sec is 4.534 m

6 0
2 years ago
Testosterone is used to treat breast cancer ? True or false?
Triss [41]

Answer:

True

Explanation:

Because I had a test on this

7 0
2 years ago
If the range of a projectile's trajectory is six times larger than the height of the trajectory, then what was the angle of laun
zvonat [6]

Answer:

H = 1/2 g t^2    where t is time to fall a height H

H = 1/8 g T^2   where T is total time in air  (2 t  = T)

R = V T cos θ       horizontal range

3/4 g T^2 = V T cos θ       6 H = R    given in problem

cos θ = 3 g T / (4 V)           (I)

Now t = V sin θ / g     time for projectile to fall from max height

T = 2 V sin θ / g

T / V = 2 sin θ / g

cos θ = 3 g / 4 (T / V)     from (I)

cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ

tan θ = 2/3      

θ = 33.7 deg

As a check- let V = 100 m/s

Vx = 100 cos 33.7 = 83,2

Vy = 100 sin 33,7 = 55.5

T = 2 * 55.5 / 9.8 = 11.3 sec

H = 1/2 * 9.8 * (11.3 / 2)^2 = 156

R = 83.2 * 11.3 = 932

R / H = 932 / 156 = 5.97        6 within rounding

3 0
2 years ago
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