Answer:
V' = V/2
Explanation:
The voltage across a parallel plate capacitor is given as follows:
V = Q/C
where,
V = Voltage across capacitor
Q = Charge on Capacitor
C = Capacitance of Capacitor = A∈₀/d
Therefore,
V = Qd/A∈₀
where,
A = Area of plate
d = distance between plates
∈₀ = permittivity of free space
FOR CAPACITOR 1:
Q = Q
d = d
A = A
V = V
Therefore,
V = Qd/A∈₀ --------------- equation (1)
FOR CAPACITOR 2:
V' = ?
Q' = Q
d' = d
A' = 2A
Therefore,
V' = Q'd'/A'∈₀
V' = Qd/2A∈₀
V' = (1/2)(Qd/A∈₀)
using equation (1):
<u>V' = V/2</u>
<h3>Answer:- </h3><h3>16000 </h3><h3> Explanation:-</h3><h3 /><h3>force = 800N</h3><h3>area of 1 feet = 0.025</h3><h3>Area of 2 feet= 0.025+0.025 = 0.050m²</h3><h3>presure = force / area </h3><h3> = 800 N / 0.050</h3><h3> = 16000</h3>
The tension in rope C is determined as 122.23 N.
<h3>Tension in rope C</h3>
The tension in rope C is calculated as follows;
B² = A² + C²
C² = B² - A²
C² = (752²) - (742²)
C² = 14,940
C = √14,940
C = 122.23 N
Thus, the tension in rope C is determined as 122.23 N.
Learn more about tension here: brainly.com/question/24994188
#SPJ1
The third option seems correct. Using any bag more than once will help in decreasing the carbon foot print.
This isds beause, if you use paper bag once only, then paper bag is being utilised and more and more paper is being used. So the best way is to use the bag more than once, whichever bag u are using.
