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-BARSIC- [3]
3 years ago
11

In a loop-the-loop ride a car goes around a vertical, circular loop at a constant speed. The car has a mass m = 268 kg and moves

with speed v = 16.24 m/s. The loop-the-loop has a radius of R = 10.5 m.
What is the magnitude of the normal force on the care when it is at the bottom of the circle? (But as the car is accelerating upward.)

2) What is the magnitude of the normal force on the car when it is at the side of the circle (moving vertically upward)?

3) What is the magnitude of the normal force on the car when it is at the top of the circle?
Physics
1 answer:
11111nata11111 [884]3 years ago
7 0
Before we go through the questions, we need to calculate and determine some values first.

r = 11.5 m 
<span>m = 280 kg </span>
<span>Centripetal force = m x v^2/r = 280 x (17.1^2/11.5) = 7119.55 N 
</span>
1) What is the magnitude of the normal force on the care when it is at the bottom of the circle. 

<span>Centripetal force + mg = 7119.55 + (280 x 9.8) = 9863.55 N </span>

<span>2) What is the magnitude of the normal force on the car when it is at the side of the circle. </span>

<span>Centripetal force = 7119.55 N </span>


<span>3) What is the magnitude of the normal force on the car when it is at the top of the circle. </span>

<span>Centripetal force - mg = 7119.55 - (280 x 9.8) = 4375.55 N </span>

<span>4) What is the minimum speed of the car so that it stays in contact with the track at the top of the loop. </span>

√<span>(gr) </span>

√<span>(9.8 x 11.5) = 10.62 m/s</span>
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Delvig [45]

Answer:

a. Acceleration = 1.75 m/s²

b. Force = 105 Newton.

Explanation:

<u>Given the following data:</u>

Mass = 60kg

Final velocity = 7m/s

Time = 4 seconds

Required to find the acceleration and force of the body;

a. To find the acceleration;

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Where;

  • a is acceleration measured in ms^{-2}
  • v and u is final and initial velocity respectively, measured in ms^{-1}
  • t is time measured in seconds.

Since the elevator is starting from rest, its initial velocity is equal to 0m/s.

Substituting into the equation, we have;

Acceleration = \frac{7 - 0}{4}

Acceleration = \frac{7}{4}

<em>Acceleration = 1.75 m/s²</em>

b. To find the force;

Force = mass * acceleration

Substituting into the equation, we have;

Force = 60 * 1.75

<em>Force = 105 Newton. </em>

4 0
2 years ago
Three blocks are arranged in a stack on a frictionless horizontal surface. The bottom block has a mass of 37.0 kg. A block of ma
Alex777 [14]

Answer:

N₂ = 503.8 N

Explanation:

given,

mass of bottom block = 37 Kg

mass of middle block = 18 Kg

mass of the top block = 16 Kg

force acting on the top block = 170 N

force on the block at top

N₁ be the normal force from block at middle

now,

N₁ = 170 + m g

N₁ = 170 + 16 x 9.8

now, force on block at middle

N₂ be the normal force exerted by the bottom block

N₂ = N₁ + m₂ g

N₂ = 326.8 + 18 x 9.8

N₂ = 503.8 N

hence, normal force by bottom block is equal to N₂ = 503.8 N

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3 years ago
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 30.0 min
schepotkina [342]

Answer:

Average speed of the trip = 52.9 km/h

Distance between initial pairs of cities (start to end) = 70.0 km

Explanation:

Since distance = speed × time

If she drives 30.0 min at 80.0 km/h

Distance covered = (30/60) × 80 = 40.0 km

Again she drives 45.0 min at 40 km/h

Distance covered = (45/60) × 40 = 30.0 km

Again she drives 12.0 min at 100 km/h

Distance covered = (12/60) × 100 = 20.0 km

Total distance covered =  40.0 + 30.0 + 20.0

                                       = 90.0 km

Total time spent = 30.0 + 45.0 + 12.0 +15.0

                           = 102 min

Average speed for the trip = Total distance covered/total time spent

                                             = 90/(102/60)

                                             = 52.9 km/h

Distance between initial cities will be between the start of one city to the end of another

Between the first pairs = 40.0 + 30.0 = 70.0 km

Between the second pairs = 30.0 + 20.0 = 50.0 km

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3 years ago
Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes th
Airida [17]
F = G m1*m2 / r^2 => [G] = [F]*[r]^2 /([m1]*[m2]) = N * m^2 / kg^2

That is one answer.

Also, you can use the fact that N = kg*m/s^2

[G] = kg * m / s^2 * m^2 / kg^2 = m^3 /(s^2 * kg)
5 0
3 years ago
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
eduard
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7 0
3 years ago
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