Answer:
The cell address of 4th row and 4th column is
4D/D4
Perhaps instead of cubicles, desks are organized in an open workspace which promotes collaboration (and makes it easier).
// C++ switch
// It can also be used for JAVA, C#
switch(age){
// here age will be sent by the function in which it is used
// case to check the age<2
case(age<2 && age>0):
// printing the line
cout<<"ineligible";
// case to check the age ==2
case(age==2):
// printing the line
cout<<"toddler";
// case to check 3-5
case(age>=3 && age<=5):
cout<<"early childhood";
// case to check 6-7
case(age==6 || age==7):
cout<<"young reader";
//case to check 8-10
case(age>=8 && age<=10):
cout<<"elementary";
// case to check 13
case(age==13):
cout<<"impossible";
//case tocheck 14-16
case(age>=14 && age<=16):
cout<<"high school";
// case to check 17 or 18
case(age==17 || age==18):
cout<<"scholar";
//case to check >18
case(age>18);
cout<<"ineligible";
// default case
default:
cout<<"Invalid age";
}
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Answer:
def typeHistogram(it,n):
d = dict()
for i in it:
n -=1
if n>=0:
if str(type(i).__name__) not in d.keys():
d.setdefault(type(i).__name__,1)
else:
d[str(type(i).__name__)] += 1
else:
break
return list(d.items())
it = iter([1,2,'a','b','c',4,5])
print(typeHistogram(it,7))
Explanation:
- Create a typeHistogram function that has 2 parameters namely "it" and "n" where "it" is an iterator used to represent a sequence of values of different types while "n" is the total number of elements in the sequence.
- Initialize an empty dictionary and loop through the iterator "it".
- Check if n is greater than 0 and current string is not present in the dictionary, then set default type as 1 otherwise increment by 1.
- At the end return the list of items.
- Finally initialize the iterator and display the histogram by calling the typeHistogram.
