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Zolol [24]
2 years ago
5

Suppose there are 4,000 bacteria in a sample. The population of the bacteria doubles exponentially every hour how many hours wil

l it take for the bacteria to reach a population of 50,000
Mathematics
1 answer:
aleksley [76]2 years ago
6 0
After 4 hours there will be 64 000

3 - 32k
2-16
1-8

do you need exactly 50 000?
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The difference of the product of 3 and m<br> minus the quotient of m divided by 2<br> m=6
s2008m [1.1K]

Answer:5m/2

Step-by-step explanation:

3m-m/2

(2×3m-1×m)/2

(6m-m)/2=5m/2

5 0
3 years ago
The poster shows how many of its games of football team has won so far.Express this information as a fraction a,percent and as a
Harrizon [31]
12/15
Divide 12 by 15 and then you should get 0.8
0.8 is obviously equal to 8/10ths or 80% 
Hope this helps :)
4 0
3 years ago
What is 5 1/4 x 4 1/5
dalvyx [7]

Answer:

The answer to your question is 22 1/20

5 0
3 years ago
Read 2 more answers
Anne,Ryan and Joel collect empty cans for recycling. They collect a total of 1,925 cans. Anne collects half as many cans as Ryan
elixir [45]
A + R + J = 1925
A = 1/2R
J = 2R

1/2R + R + 2R = 1925
7/2R = 1925
R = 550

J = 2(550)
J = 1100

Joel collects 1100 cans.
3 0
3 years ago
Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?
Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so


\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}


so we're really looking for a line whose slope is 3 and runs through (1,5)


\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2

4 0
3 years ago
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