1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksivusya [100]
3 years ago
7

A 5.00-kg object is initially at rest. The object is acted on by a 9.00-N force toward the east for 3.00 s. No force acts on the

object for the next 4.00 s. How far has the object moved during this 7.00 s interval?
Physics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

The total distance at 7 s is:

x_{tot}=27\: m

Explanation:

<u>Distance due to the force</u>

We can use second Newton's law to find the acceleration.

F=ma

a=\frac{F}{m}=\frac{9}{5}=1.8\: m/s^{2}

Now, using the kinematic equation we will find the distance during this interval of time. Let's recall that the initial velocity is zero.

x_{1}=0.5at_{1}^{2}

x_{1}=0.5(1.8)(3)^{2}

x_{1}=8.1\: m

In the second part of the motion, the object moves at a constant velocity, as long as there is no friction between the object and the floor.

First, we need to find the final velocity of the first interval

v=v_{i}+at_{1}=0+(1.8)3=5.4\: m/s

So the second distance will be:

x_{2}=vt_{2}=5.4*4=21.6\: m

Therefore, the total distance is:

x_{tot}=x_{1}+x_{2}=5.4+21.6=27\: m

I hope it helps you!

You might be interested in
What is the equivalet tempreture of 0 kelvin in celcius scale <br> HELP NEED IT IN 5 MIN
Alona [7]

Answer:

-273.15 degree celcius

Explanation:

7 0
3 years ago
Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular
RUDIKE [14]

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, \omega _i = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

6 0
3 years ago
Each corner of a right-angled triangle is occupied by identical point charges "A", "B", and "C" respectively. Draw a sketch of t
NISA [10]

Answer:

Fnet = F√2

Fnet = kq²/r² √2

Explanation:

A exerts a force F on B, and C exerts an equal force F on B perpendicular to that.  The net force can be found with Pythagorean theorem:

Fnet = √(F² + F²)

Fnet = F√2

The force between two charges particles is:

F = k q₁ q₂ / r²

where

k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.

If we say the charge of each particle is q, then:

F = kq²/r²

Substituting:

Fnet = kq²/r² √2

5 0
3 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n
hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N  

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m  

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)  

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q =  r*sq rt F[4pieo]

 q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

 891 excess electrons must be present on each sphere  

5 0
3 years ago
These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg
Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C

Calculating the common potential:

\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\

Calculating the charge after redistribution:

When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2        

\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\  \\  \to               q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C

6 0
3 years ago
Other questions:
  • An engineer is working on a new kind of wire product that is about the size of a bacterium cell. Which kind of technology is the
    7·2 answers
  • What is the kinetic energy k of the two-car system immediately after the collision? express your answer in terms of ve, vn, and
    6·1 answer
  • Particle a has twice the charge of nearby particle
    12·1 answer
  • In a series RCL circuit the generator is set to a frequency that is not the resonant frequency. This nonresonant frequency is su
    15·1 answer
  • What would be the weight of a 59.1-kg astronaut on a planet with the same density as Earth and having twice Earth's radius?
    14·1 answer
  • Maggie is a member of her school’s environmental club and is interested in recycling. She asks the question, “How does exposure
    13·1 answer
  • What are 3 ways to say velocity is decreasing
    7·1 answer
  • An object moves along the x-axis. Its position is given by the equation y( X = 4t^2 - 41t+ 78 \). Find the position of the
    11·1 answer
  • Pls help will mark brain
    10·1 answer
  • Atoms of the gas neon
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!