Answer:
They form a covalent bond
1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.
It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.
Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
To know more about 1-H NMR spectroscopy
brainly.com/question/20111886
#SPJ4
Explanation:
Sodium has 1 electron in its outermost shell, and chlorine has 7 electrons. It is easiest for sodium to lose its electron and form a +1 ion, and for chlorine to gain an electron, forming a -1 ion.
<em>Now ionic bonds areIons are formed by atoms that have non-full outermost electron shells in order to become more like the noble gases in Group 8 of the Periodic Table,</em>
<em>Now ionic bonds areIons are formed by atoms that have non-full outermost electron shells in order to become more like the noble gases in Group 8 of the Periodic Table,Some atoms add electrons to get a full shell, thus becoming a negative ion. Other atoms subtract electrons from their outermost shell, leaving a full </em><em>shell and an overall positive charge..</em>
<em>shell and an overall positive charge..therefore it is an</em> ionic bond
Answer:
0.39760273
Explanation:
I typed into calculator hope it's right.