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Over [174]
3 years ago
15

3. Automobile companies often test the safety of cars by putting them through crash tests to observe the integrity of the passen

ger compartment. If 1100kg car is sent toward a cement wall with a speed of15 m/s, an impact force of 185,000 N stops the car, how long does it take before the car is brought to a stop?​
Physics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

Time taken for car to stop = 0.89 seconds (Approx.)

Explanation:

Given:

Mass of car = 1100 kg

Speed of car = 15 m/s

Impact force = 185,000 N

Find:

Time taken for car to stop

Computation:

Change in momentum of car = M(v) - M(u)

Change in momentum of car = 1100(0) - 1100(15)

Change in momentum of car = -16,500

Time taken for car to stop = I Change in momentum of car I / Impact force

Time taken for car to stop = I-16,500I / 185,000

Time taken for car to stop = 0.89 seconds (Approx.)

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The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

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  • Tension on second rope; T_2 =\ ?

To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

F = m\ *\ a

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity  g = 9.8m/s^2 )

For the First Rope

Total mass hanging on it; m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg

So Tension of the rope;

F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N

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Answer:

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Neutral is simply 7, in the middle of the scale.

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Temperature is a measure of how much the atoms in a substance are moving. Why is a substance hotter in the gas state than in the
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Hey there!
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