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3 years ago

What is equivalent to 5:2

Mathematics

1 answer:

kozerog [31]3 years ago

3 0

Answer:

2.5:1 or 2.5

Step-by-step explanation:

5/2 ÷ 2 would give you 2.5/1 or 2.5

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What is y=-4/3x +6. y=2

Mekhanik [1.2K]

The given equation is:
[/tex]y=-\frac{4}{3}x+6 [/tex] and we need to evaluate this for y=2.
So, first step is to plug in 2 for y in the above equation. Therefore,

$2=-\frac{4}{3} x+6$
$2*3=-\frac{4}{3} x*3+6*3$ Multiply each sides by common denominator 3
$6=-4x+18$
6-18= -4x Subtract 18 from each sides.
-12=-4x
$-\frac{12}{-4} =-\frac{4x}{-4}$
So, x=3

5 0

2 years ago

Determine the value of the variable that makes the equation true. 12-b=12.5

dusya [7]

Answer:

B = -.5

Step-by-step explanation:

If B is negative is cancels out the prexisting negative making it positive.

6 0

2 years ago

Factor the polynomial. 7x2 + 68xy - 20y2 A) (7x - 2y)(x + 10y) B) (7x - 10y)(x - 2y) C) (7x + 10y)(x + 2y) D) (7x + 2y)(x - 10y)

Otrada [13]

For this case we have the following polynomial:
7x2 + 68xy - 20y2
Factoring we have:
(7x-2y) (x + 10y)
We verify the factorization:
7x2 + 70xy - 2xy - 20y2
Rewriting we have:
7x2 + 68xy - 20y2
Therefore, the factorization is correct.
Answer:
A) (7x - 2y) (x + 10y)

5 0

3 years ago

Plz guys help i need asap<br> its part b im stuck

aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

4 0

3 years ago

Which 30 60 90 triangle is labled with the correct side length ratio

Evgesh-ka [11]

Isosceles triangle.

6 0

3 years ago